[英]Python: create new column conditionally on values from two other columns
I would like to combine two columns in a new column.我想将两列合并到一个新列中。
Lets suppose I have:假设我有:
Index A B
0 1 0
1 1 0
2 1 0
3 1 0
4 1 0
5 1 2
6 1 2
7 1 2
8 1 2
9 1 2
10 1 2
Now I would like to create a column C with the entries from A from Index 0 to 4 and from column B from Index 5 to 10. It should look like this:现在我想创建一个列 C,其中包含 A 中索引 0 到 4 的条目以及 B 列中索引 5 到 10 中的条目。它应该如下所示:
Index A B C
0 1 0 1
1 1 0 1
2 1 0 1
3 1 0 1
4 1 0 1
5 1 2 2
6 1 2 2
7 1 2 2
8 1 2 2
9 1 2 2
10 1 2 2
Is there a python code how I can get this?有 python 代码吗? Thanks in advance!
提前致谢!
If Index
is an actual column you can use numpy.where
and specify your condition如果
Index
是实际列,您可以使用numpy.where
并指定您的条件
import numpy as np
df['C'] = np.where(df['Index'] <= 4, df['A'], df['B'])
Index A B C
0 0 1 0 1
1 1 1 0 1
2 2 1 0 1
3 3 1 0 1
4 4 1 0 1
5 5 1 2 2
6 6 1 2 2
7 7 1 2 2
8 8 1 2 2
9 9 1 2 2
10 10 1 2 2
if your index is your actual index如果您的索引是您的实际索引
you can slice your indices with iloc and create your column with concat.您可以使用 iloc 对索引进行切片,并使用 concat 创建列。
df['C'] = pd.concat([df['A'].iloc[:5], df['B'].iloc[5:]])
print(df)
A B C
0 1 0 1
1 1 0 1
2 1 0 1
3 1 0 1
4 1 0 1
5 1 2 2
6 1 2 2
7 1 2 2
8 1 2 2
9 1 2 2
10 1 2 2
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