使用 python 中的列表对嵌套字典进行排序

Question

I have a python dict that is like

flights = [
    {
        "Flight_Fare": [
            {"M": {"AvailableSets": "9+", "AdultBaseFare": "20"}},
            {"N": {"AvailableSets": "9+", "AdultBaseFare": "30"}},
        ]
    },
    {
        "Flight_Fare": [
            {"M": {"AvailableSets": "9+", "AdultBaseFare": "40"}},
            {"N": {"AvailableSets": "9+", "AdultBaseFare": "10"}},
        ]
    },
]

I would like to sort the ' Flights ' list based on the value of the object that has the cheapest price inside ' Flight_Fare ' under its ' AdultBaseFare '.

So you can look at it like this,

each object inside ' Flights ' is for a flight and each flight has different classes (ex. one for Economy one for Bussiness) and each class has a different price. I want to sort the whole " Flight " list so that the first object inside the ' Flight ' list is the flight that has the cheapest price (doesn't matter if the other class in that flight is more expensive then the next flight)

I think the best way would be to first sort the ' Flight_Fare ' list of each Flight (so that each flight has its classes sorted based on the price) and then sort the ' Flight ' list based on the price of the first object in ' Flight_Fare ' in that flight.

can someone please help me with this?

Answer 1

just make a function to get the cheapest adultbasefare for each flight and use it as the key for the sorted function

def get_cheapest(flight):
    fares = []
    for f in flight['Flight_Fare']:
        for key in f.keys():
            fares.append(f[key]['AdultBaseFare'])
    return float(min(fares))

flights = [
    {
        "Flight_Fare": [
            {"M": {"AvailableSets": "9+", "AdultBaseFare": "20"}},
            {"N": {"AvailableSets": "9+", "AdultBaseFare": "30"}},
        ]
    },
    {
        "Flight_Fare": [
            {"M": {"AvailableSets": "9+", "AdultBaseFare": "40"}},
            {"N": {"AvailableSets": "9+", "AdultBaseFare": "10"}},
        ]
    },
]

out = sorted(flights, key=lambda x: get_cheapest(x))