将大文本文件与 python 合并

Question

I have a bunch of text files that have the next format

word(1) num(1,1) num(1,2) num(1,3) ... num(1,300)
word(2) num(2,1) num(2,2) num(2,3) ... num(2,300)
word(3) num(3,1) num(3,2) num(3,3) ... num(3,300)
...
word(n) num(n,1) num(n,2) num(n,3) ... num(n,300)

The name of the files is palabrasX.txt where X is a number that represents the length of the strings that makes the words inside the files (which go from 1 to 32), so for example if the word is "cat" then should be inside palabras3.txt

Then the real problem is that some of these files are too big to open by normal means, and I want to make one big file that has all the information of these files, so I would have all the words with 1 character first then all the words with 2 and so on until 32

I'm trying something like this:

# encoding: utf-8
filenames = {}
for i in range(32):
    filenames[i]="palabras"+str(i+1)+".txt"
    with open("VectoresPalabrasEspañol\TodasMisPalabras.txt", "w") as outfile:
        for fname in filenames:
            with open(fname) as infile:
                for line in infile:
                    outfile.write(line)

but it stays in a working state, so I'm not sure if I have a problem with the logic, or if I triggered an infinite loop or something else.

by the way, the path for the full file is:

"VectoresPalabrasEspañol\TodasMisPalabras.txt"

and the path for the palabraX.txt is:

f"palabras\Probables palabras\palabras{length}.txt"

Answer 1

you can code this way

here file path is current directory

import os

filenames = []

for i in range(32):
    filenames.append("palabras"+str(i+1)+".txt")

with open("TodasMisPalabras.txt", "w") as outfile:
        for fname in filenames:
            # fname=fname[1]
            if os.path.exists(fname):
                with open(fname) as infile:
                    for line in infile:
                        outfile.write(line)