[英]remove space in string array and count spaces C
I have a string line with an array.我有一个带有数组的字符串行。 Ex:- char array[]="I'm new to programing";
例如:- char array[]="I'm new to programing";
I want to rewrite code that variable remove spaces array[]="I'mnewtoprograming"
我想重写变量删除空格array[]="I'mnewtoprograming"
的代码
I already tried to build this我已经尝试过构建这个
scanf("%[^\n]s",&line);
int len=strlen(line);
//remove space in lenth
for(int i=0;i<len;i++)
(line[i]==' ')?:newlen++;
if (line[i]==' ')
{
line[i]=line[i+1];
}
give me the reason that I mistake给我错误的理由
You need to keep track of the current position in the string and the "tail" where next char is compared to the space.您需要跟踪字符串中当前的 position 以及将下一个字符与空格进行比较的“尾部”。
char *removechar(char *str, int ch)
{
char *cpos = str, *tail = str;
while(*tail)
{
if(*tail != ch)
{
*cpos++ = *tail++;
}
else
{
tail++;
}
}
*cpos = 0;
return str;
}
Make For loop for array[]
and count ' '
spaces.为array[]
创建 For 循环并计算' '
空格。 line[i]=line[i+1];
this line is wrong.这条线是错误的。
(line[i]==' ')?:newlen++;
this line is correct, i saw some comments that line was wrong.its same as if condition.这条线是正确的,我看到一些评论说这条线是错误的。它与 if 条件相同。
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