int variable_name(0); 是什么？ 意思是？

Question

I'm learning C in school and could not find any anything about this line of code

int numLetter(0);

We are currently learning about pointers. This line does not show up until the end of a for loop where we add 1 every time a case was satisfied.

++numLetter;

Going back to my question on the title. What does int variable(0); mean? Is it the same as initializing a variable like

int numLetter = 0;

EDIT: Thank you for the response. In the example I was given we are trying to do pointer arithmetic. The sample code is below:

const size_t arr_len = 7;
char name[arr_len] = "Marzian";
int numVow(0);

for (char *ptr = name; ptr < name + arr_len; ++ptr) 
{
    switch (*ptr)
    {
        case "A":
        case "a":
        case "E":
        case "e":
        case "I":
        case "i":
        case "O":
        case "o":
        case "U":
        case "u":
            +++numVow;
    }
}

I thought int numLetter(0); has something to do with pointer syntax. But like you guys have mentioned it is not a valid C syntax. My professor might have just mixed up the syntax when he made this example. While I am here. Do you guys have any resources to understand pointer a lot better? Im not used to pointer/address I never used something similar when I was practicing python.

Thanks everyone for the help!

Answer 1

This isn't a valid syntax in C language.

But in C++, The value is being initialized to zero in the syntax given. You could say that:

int x(0);
int y = 0;

Both of the aforementioned statements are valid and equivalent to each other and they've nothing related to the pointers.