我在 Mac 中使用 java 运行 curl 命令时遇到以下错误，它给出 IOException 并说无法运行程序

Question

Below is my curl for a POST request in java:

String payload1 = "curl --location --request POST 'https://some_url/abc' \\\n" +
                    "--header 'Api-Key: RIQOWU-9asds943msd9d934nmwdw0d' \\\n" +
                    "--header 'Content-Type: application/json' \\\n" +
                    "--header 'BarId: di292sdk/dmasdaskdnasd934n3sda0334n5Yz1QlVnnTmJ39U4aJT8/9sdns/Xwpen/asdksaeibwae+292nsadsaweg3ARyWwAA0LuSDIL3s+A/EVkLoVhc=' \\\n" +
                    "--header 'Accept: application/json;v=2' \\\n" +
                    "--header 'Cookie: JSESSIONID=9SDKSDSD9M23B4D46BF663F2B51E75137' \\\n" +
                    "--data-raw '{\n" +
                    "\"AU\": \"EC\",\n" +
                    "    \"is\": \"is\",\n" +
                    "    \"ls\": \"js\",\n" +
                    "    \"Timestamp\": \"2021-06-26T18:43:00Z\"\n" +
                    "}'";
            ProcessBuilder process = new ProcessBuilder(payload1);
            Process p;
            p = process.start();

Below is the relevant data from response

java.io.IOException: Cannot run program "/usr/local/Cellar/curl/7.71.1/bin/curl.exe --location --request POST '..........
: error=2, No such file or directory
    at java.lang.ProcessBuilder.start(ProcessBuilder.java:1048)
    at com.aws.s3.service.EntryPoint.POSTAPI(EntryPoint.java:343)
    at com.aws.s3.service.EntryPoint.main(EntryPoint.java:72)
Caused by: java.io.IOException: error=2, No such file or directory
    at java.lang.UNIXProcess.forkAndExec(Native Method)
    at java.lang.UNIXProcess.<init>(UNIXProcess.java:247)
    at java.lang.ProcessImpl.start(ProcessImpl.java:134)
    at java.lang.ProcessBuilder.start(ProcessBuilder.java:1029)
    ... 2 more

Process finished with exit code 0

I've tried mentioning the path of curl too in the String like below but still getting the same error.

String payload1 = "/usr/local/Cellar/curl/7.71.1/bin/curl.exe "+"--location --request POST......above payload......"

Please let me know if what could be the cause of it not able to interpret curl command in java. Greatly appreciated!!

Answer 1

Are you certain the path to curl is correct - does it end ".exe"? I would have thought Mac version had no ".exe". Validate the executable path used in the call with:

 File curl = new File("/usr/local/Cellar/curl/7.71.1/bin/curl"); 
 System.out.println("curl.exists()="+curl.exists());
 System.out.println("Files.isExecutable()="+Files.isExecutable(curl.toPath()));

Runtime.exec has Runtime.exec(String) but there is no ProcessBuilder(String) - that has ProcessBuilder(String...) . As your parameter is complex switch to String[], and this rules out issue with punctuation inside your command which will not require the line continuation values \\\n :

 String [] payload1 = new String[] { curl.getAbsolutePath(), 
       "--location", "--request", "POST"
     , "https://some_url/abc"
     , "--header", "Api-Key: RIQOWU-9asds943msd9d934nmwdw0d"
     
 ... etc

     , "--data-raw", "{\n" +
                "\"AU\": \"EC\",\n" +
                "    \"is\": \"is\",\n" +
                "    \"ls\": \"js\",\n" +
                "    \"Timestamp\": \"2021-06-26T18:43:00Z\"\n" +
                "}"
 };

Now you have Pipe errors, so if you send data to the process getOutputstream you should close() it, and ideally redirect the process output and error streams to file with:

process.redirectOutput(file); process.redirectError(file):