如何返回两个列表之间的不匹配

Question

I have two lists, each with several elements in them:

list_2 = ['https://josh.ucc.edu/just-go-grind-125/','https://josh.ucc.edu/thirty-minute-kayak-2/', 'https://josh.ucc.edu/fight-online-t-shirts-help-support-local-businesses/']
matchers = ['just-go-grind', 'thirty-minute']

I would like to use list comprehension to return not matches between the two lists. This is what I've tried:

not_matching = [s for s in list_2 if None(xs in s for xs in matchers)]
print(not_matching)

output:

not_matching = [s for s in list_2 if None(xs in s for xs in matchers)]]
                                                                       ^
SyntaxError: invalid syntax

I don't think I am using the list comprehension correctly but am unsure how to print a non-match, any ideas? Thanks!

Answer 1

I think you're looking for any built-in function of python:

not_matching = [s for s in list_2 if not any(xs in s for xs in matchers)]

Output:

not_matching
['https://josh.ucc.edu/fight-online-t-shirts-help-support-local-businesses/']