是否可以声明关闭的返回类型？

Question

I'm learning closure in scala programming language.

For example:

val a = (x:Int, y:Int) => x + y;
a(1, 2)

will give me 3 . the closure a works like a function (Int, Int):Int .

Is it possible to declare the return type for closure like this?

val a = (x:Int, y:Int):Int => x + y;
a(1, 2)

Is it possible?

Answer 1

This syntax is impossible ( val a = (x:Int, y:Int):Int => x + y ), but you can declare type for a :

val a: (Int, Int) => Int = (x, y) => x + y