将 Python 列表项分解为较小的列表，替换新的子列表项，并将列表与新值重新组合在一起

Question

I'm not sure how to do this, so apologies for any confusion.

I would like to take a list containing sentences, and break the sentences down into a smaller sub list.

Somehow, I was hoping to replace an item in new sub list, and return the list back with it's new value.

For example:

txt_lst = ['That is Jays sock.', 'It is green.', 'Leave it there.']

Then I want to take txt_lst[0] , and make a new sub_txt_lst:

sub_txt_lst = ['That', 'is', 'Jays', 'sock.']

And replace the item sub_txt_lst[2] with her .

Afterwards, I would like txt_lst to read:

txt_lst = ['That is her sock.', 'It is green.', 'Leave it there.']

Again, sorry if this explanation is poorly written.

Answer 1

You can use re to do this in an efficient way:

import re

txt_lst = ['That is Jays sock.', 'It is green.', 'Leave it there.']
print([re.sub(r'\bJays\b', 'her', x) for x in txt_lst])

# ['That is her sock.', 'It is green.', 'Leave it there.']

Answer 2

Here ya go:

txt_lst = ['That is Jays sock.', 'It is green.', 'Leave it there.']
sub_txt_lst = txt_lst[0].split()
sub_txt_lst[2] = "her"
txt_lst[0] =  " ".join(sub_txt_lst)

Or if you'd like to just modify a specific word:

txt_lst[0] = txt_lst[0].replace("Jays","her")

Both yield:

['That is her sock.', 'It is green.', 'Leave it there.']