将列从 StringType 转换为 Json（对象）

Question

Here is a sample data

val df4 = sc.parallelize(List(
  ("A1",45, "5", 1, 90),
  ("A2",60, "1", 1, 120),
  ("A6", 30, "9", 1, 450),
  ("A7", 89, "7", 1, 333),
  ("A7", 89, "4", 1, 320),
  ("A2",60, "5", 1, 22),
  ("A1",45, "22", 1, 1)
)).toDF("CID","age", "children", "marketplace_id","value")

thanks to @Shu for this piece of code

val df5 = df4.selectExpr("CID","""to_json(named_struct("id", children)) as item""", "value", "marketplace_id")

+---+-----------+-----+--------------+
|CID|item       |value|marketplace_id|
+---+-----------+-----+--------------+
|A1 |{"id":"5"} |90   |1             |
|A2 |{"id":"1"} |120  |1             |
|A6 |{"id":"9"} |450  |1             |
|A7 |{"id":"7"} |333  |1             |
|A7 |{"id":"4"} |320  |1             |
|A2 |{"id":"5"} |22   |1             |
|A1 |{"id":"22"}|1    |1             |
+---+-----------+-----+--------------+

when you do df5.dtypes

(CID,StringType), (item,StringType), (value,IntegerType), (marketplace_id,IntegerType)

the column item is of string type, is there a way this can be of json/object type(if that is a thing)?

EDIT 1: I will describe what I am trying to achieve here, the above two steps remains same.

val w = Window.partitionBy("CID").orderBy(desc("value"))
val sorted_list = df5.withColumn("item", collect_list("item").over(w)).groupBy("CID").agg(max("item") as "item")

Output:

+---+-------------------------+
|CID|item                     |
+---+-------------------------+
|A6 |[{"id":"9"}]             |
|A2 |[{"id":"1"}, {"id":"5"}] |
|A7 |[{"id":"7"}, {"id":"4"}] |
|A1 |[{"id":"5"}, {"id":"22"}]|
+---+-------------------------+

now whatever is inside [ ] is a string. which is causing a problem for one of the tools we are using.

Sorry, pardon me I am new to scala, spark if this is a basic question.

Answer 1

Store json data using struct type, check below code.

scala> dfa
.withColumn("item_without_json",struct($"cid".as("id")))
.withColumn("item_as_json",to_json($"item_without_json"))
.show(false)

+---+-----------+-----+--------------+-----------------+------------+
|CID|item       |value|marketplace_id|item_without_json|item_as_json|
+---+-----------+-----+--------------+-----------------+------------+
|A1 |{"id":"A1"}|90   |1             |[A1]             |{"id":"A1"} |
|A2 |{"id":"A2"}|120  |1             |[A2]             |{"id":"A2"} |
|A6 |{"id":"A6"}|450  |1             |[A6]             |{"id":"A6"} |
|A7 |{"id":"A7"}|333  |1             |[A7]             |{"id":"A7"} |
|A7 |{"id":"A7"}|320  |1             |[A7]             |{"id":"A7"} |
|A2 |{"id":"A2"}|22   |1             |[A2]             |{"id":"A2"} |
|A1 |{"id":"A1"}|1    |1             |[A1]             |{"id":"A1"} |
+---+-----------+-----+--------------+-----------------+------------+

Answer 2

Based on the comment you made to have the dataset converted to json you would use:

df4
  .select(collect_list(struct($"CID".as("id"))).as("items"))
  .write()
  .json(path)

The output will look like:

{"items":[{"id":"A1"},{"id":"A2"},{"id":"A6"},{"id":"A7"}, ...]}

If you need the thing in memory to pass down to a function, instead of write().json(...) use toJSON