在数组上均匀分布 boolean 值（Javascript）

Question

I have a boolean array with a fixed length. Values are defaulted to false .
I need to fill the array with N values of true , that are mostly evenly distributed and spreaded over the array.

For example: If length is 7 and N is 3, it would look something like this:
[false, true, false, true, false, true, false]

If length is 14 and N is 5, it would look something like this:
[false, false, true, false, false, true, false, false, true, false, true, false, true, false]

The thing is, there isn't a strict rule of how to spread it, only that it should be spreaded mostly in an even matter (perhaps with a rule that the first and last elements won't be true, but not necessary).

Answer 1

 function createBoolArray(len, trues) { const arr = new Array(len).fill(false); let leftTrues = trues; let left = len; let divisor = 0; for(let i = 0; i < len && leftTrues > 0;) { left = len - i; divisor = Math.floor(left / leftTrues); if(Math.floor(left / divisor) > leftTrues) { i = i + divisor + 1; arr[i - 1] = true; } else { i = i + divisor; arr[i - 1] = true; } leftTrues--; } return arr; } console.log(createBoolArray(14, 5))

Answer 2

Ended up doing this (similar to what @ChrisG suggested):

function createBoolArray(len, trues) {
  const arr = new Array(len).fill(false);
  new Array(trues).fill(0).map((_, i) => 
  Math.floor((i+1) * (len-1) / trues))
 .forEach(e => arr[e] = true);

  return arr;
}

console.log(createBoolArray(14, 5))