Ruby 正则表达式捕获两个字符串之间的部分内容

Question

With ruby gsub() , in string <code>balabala or blank \n another balabala or blank</code> , replacing all \n inside <code>...</code> block into <br> , but do nothing to the content outside <code>...</code> .

I tried /<code>.*(\\n?).*<\/code>/ but not working:

html = '<pre>do \n nothing<code>line \n break</code></pre>'

html = html.gsub(/<code>.*(\\n?).*<\/code>/) { "<br>" }

print html

# actual result: <pre>do \n nothing<br></pre>

# expect result: <pre>do \n nothing<code>line <br> break</code></pre>

Answer 1

Match all substrings between <code> and </code> and replace all \n with <br> in those matches only:

html = html.gsub(/<code>.*?<\/code>/m) { $~[0].gsub('\n', '<br>') }