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如何迭代字符串对象中的特定元素(arraylist Java)

[英]how to iterate over specific elements in string objects (arraylist Java)

ArrayList<String> dnaArray = new ArrayList<>();
ArrayList<Character> compArray = new ArrayList<Character>();

// [tac, tat, tta, aaa, aac, aca, aac, ttt]

public void createCompliment() {
    for (String letters : dnaArray) {
        for (int i = 0, len = letters.length(); i < len; i++) {
            char character = letters.charAt(i);
            if (character == 'a'){
                character = 't';
            } else if (character == 'c') {
                character = 'g';
            }
            compArray.add(character);
        }
    }
}

How would I access specific characters, change 'a' to 't' and similarily from 'c' to 'g'.我将如何访问特定字符,将“a”更改为“t”,类似地从“c”更改为“g”。 Then added to a new arraylist and return something like:然后添加到新的 arraylist 并返回如下内容:

[ttg, ttt, ttt, ttt, ttg, tgt, ttg, ttt] [ttg,ttt,ttt,ttt,ttg,tgt,ttg,ttt]

instead of: [t, t, g, t, t, t, t, t, t, t, t, t, t, t, g, t, g, t, t, t, g, t, t, t]代替: [t,t,g,t,t,t,t,t,t,t,t,t,t,t,g,t,g,t,t,t,g,t,t,吨]

appreciate it欣赏它

the easiest way in my opinion is to use string replace:我认为最简单的方法是使用字符串替换:

ArrayList<String> dnaArray = new ArrayList<>();
ArrayList<String> compArray = new ArrayList<String>();

public void createCompliment() {
    for (String letters : dnaArray) {
        compArray.add(letters.replace('a', 't').replace('c', 'g'));
    }
}

You can use a StringBuilder() to create the new String then add it to compArray .您可以使用StringBuilder()创建新的 String 然后将其添加到compArray

Try this:尝试这个:

for(String letters : dnaArray) {
    StringBuilder sb = new StringBuilder();
    for(int i=0; i<letters.length(); i++) {
        char character = letters.charAt(i);
        if (character == 'a'){
            sb.append("t");
        }
        else if (character == 'c'){
            sb.append("g");
        } else {
            sb.append(String.valueOf(character));
        }
    }
    compArray.add(sb.toString());
}

Output: Output:

[ttg, ttt, ttt, ttt, ttg, tgt, ttg, ttt]

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