[英]How to Iterate over an ArrayList of Objects for a specific type in Java
[英]how to iterate over specific elements in string objects (arraylist Java)
ArrayList<String> dnaArray = new ArrayList<>();
ArrayList<Character> compArray = new ArrayList<Character>();
// [tac, tat, tta, aaa, aac, aca, aac, ttt]
public void createCompliment() {
for (String letters : dnaArray) {
for (int i = 0, len = letters.length(); i < len; i++) {
char character = letters.charAt(i);
if (character == 'a'){
character = 't';
} else if (character == 'c') {
character = 'g';
}
compArray.add(character);
}
}
}
我將如何訪問特定字符,將“a”更改為“t”,類似地從“c”更改為“g”。 然后添加到新的 arraylist 並返回如下內容:
[ttg,ttt,ttt,ttt,ttg,tgt,ttg,ttt]
代替: [t,t,g,t,t,t,t,t,t,t,t,t,t,t,g,t,g,t,t,t,g,t,t,噸]
欣賞它
我認為最簡單的方法是使用字符串替換:
ArrayList<String> dnaArray = new ArrayList<>();
ArrayList<String> compArray = new ArrayList<String>();
public void createCompliment() {
for (String letters : dnaArray) {
compArray.add(letters.replace('a', 't').replace('c', 'g'));
}
}
您可以使用StringBuilder()
創建新的 String 然后將其添加到compArray
。
嘗試這個:
for(String letters : dnaArray) {
StringBuilder sb = new StringBuilder();
for(int i=0; i<letters.length(); i++) {
char character = letters.charAt(i);
if (character == 'a'){
sb.append("t");
}
else if (character == 'c'){
sb.append("g");
} else {
sb.append(String.valueOf(character));
}
}
compArray.add(sb.toString());
}
Output:
[ttg, ttt, ttt, ttt, ttg, tgt, ttg, ttt]
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