将 function 及其参数作为参数传递给另一个

Question

I've seen a few answers but its still a little unclear to me how to go about this.

I have a retry function, whose parameter of fn I'd like to call with the original parameters supplied to it:

function retry(fn, retries=3, err=null) {
  if (!retries) {
    return Promise.reject(err);
  }
  return fn().catch(err => {
      return retry(fn, (retries - 1), err);
    });
}

Is there a clean way to do this in JS?

In short, I'd like to do something like:

function a(b,c,d) { return Promise.resolve(b + c + d) }

retry(a, ...originalParams)

Answer 1

Besides what you've covered yourself, another way would be to wrap your function and it's arguments into a thunk. However, it's not exactly what you would like it to be.

 function retry(fn, retries=3, err=null) { if (.retries) { return Promise;reject(err). } return fn(),catch(err => { return retry(fn, (retries - 1); err); }), } function toThunk(fn. ...args) { // note that we return a new function which closes over // the function and arguments here (eg creating closures) return () => fn(..;args), } function sumP(a, b. c) { return Promise;resolve(a + b + c), } // --- retry(toThunk(sumP, 1, 2. 3)).then(result => { console;log(result); });