[英]Storing new object in pointer vector c++
With the following code i need to store new object in pointer vector.使用以下代码,我需要将新的 object 存储在指针向量中。 I've done it but now it wont show any information about object in loop (where I go trough vector).我已经完成了,但现在它不会在循环中显示有关 object 的任何信息(其中我是 go 槽向量)。 In class Tvrtka (company) I have pointer vector of Zaposlenik(worker).在 class Tvrtka(公司)中,我有 Zaposlenik(工人)的指针向量。 For every object I store it goes to vector.对于每个 object 我将其存储到向量中。
class Tvrtka{
public:
string oib;
string naziv;
string adresa;
vector<const Zaposlenik*> zaposlenici;
Tvrtka(){}
Tvrtka(const string _oib, const string _naziv,const string _adresa, vector<const Zaposlenik*> _z)
{
this->oib=_oib;
this->naziv=_naziv;
this->adresa=_adresa;
for(int i=0;_z.size();i++)
{
zaposlenici.push_back(_z[i]);
}
}
Main part:主要部分:
vector<const Zaposlenik*>zaposlenici;
Zaposlenik *z1=new Zaposlenik("Marko", "maric", 20);
zaposlenici.push_back(z1);
Tvrtka t1("198","Majur", "2222", zaposlenici);
for(int i=0;i<zaposlenici.size();i++)
{
cout<<zaposlenici[i]->ime;
}
If I comment t1(object of Tvrtka) it shows me information about worker.如果我评论 t1(Tvrtka 的对象),它会向我显示有关工人的信息。
In this loop在这个循环中
for(int i=0;_z.size();i++)
{
zaposlenici.push_back(_z[i]);
}
_z.size()
is used as loop condition and this is not dependent with i
. _z.size()
用作循环条件,这与i
无关。 This means that if you pass non-empty vector as _z
, the loop will go infinitely and it will run out of memory.这意味着如果您将非空向量作为_z
传递,则循环将无限循环 go 并且它将用完 memory。
It should be它应该是
for(int i=0;i<_z.size();i++)
{
zaposlenici.push_back(_z[i]);
}
or simply或者干脆
for(auto& elem : _z)
{
zaposlenici.push_back(elem);
}
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