Storing new object in pointer vector c++

Question

With the following code i need to store new object in pointer vector. I've done it but now it wont show any information about object in loop (where I go trough vector). In class Tvrtka (company) I have pointer vector of Zaposlenik(worker). For every object I store it goes to vector.

class Tvrtka{
public:
    string oib;
    string naziv;
    string adresa;
    vector<const Zaposlenik*> zaposlenici;
    Tvrtka(){}
    Tvrtka(const string _oib, const string _naziv,const  string _adresa, vector<const Zaposlenik*> _z)

    {
        this->oib=_oib;
        this->naziv=_naziv;
        this->adresa=_adresa;
        for(int i=0;_z.size();i++)
        {
            zaposlenici.push_back(_z[i]);
        }
    }

Main part:

vector<const Zaposlenik*>zaposlenici;

    Zaposlenik *z1=new Zaposlenik("Marko", "maric", 20);
    zaposlenici.push_back(z1);

    Tvrtka t1("198","Majur", "2222", zaposlenici);


        for(int i=0;i<zaposlenici.size();i++)
        {


            cout<<zaposlenici[i]->ime;
        }

If I comment t1(object of Tvrtka) it shows me information about worker.

Answer 1

In this loop

for(int i=0;_z.size();i++)
{
    zaposlenici.push_back(_z[i]);
}

_z.size() is used as loop condition and this is not dependent with i . This means that if you pass non-empty vector as _z , the loop will go infinitely and it will run out of memory.

It should be

for(int i=0;i<_z.size();i++)
{
    zaposlenici.push_back(_z[i]);
}

or simply

for(auto& elem : _z)
{
    zaposlenici.push_back(elem);
}