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按列分组并获取 sql 上的最大和最小 ID

[英]Group by column and get max and min id on sql

I got a table with theses Column: ID_REAL,DATE_REAL,NAME_REAL我得到了一张包含以下列的表格:ID_REAL、DATE_REAL、NAME_REAL

I want to make a query to get result like this with a group by on the name我想查询以获得这样的结果,并根据名称进行分组

NAME | MAX(DATE_REAL) | ID_REAL of the MAX(DATE_REAL) | MIN(DATE_REAL) | ID_REAL of the MIN(DATE_REAL)

I dont know how to make it for the moment I have我现在不知道怎么做

select NAME_REAL,max(DATE_REAL),ID_REAL from MYREALTABLE group by NAME_REAL,ID_REAL
select NAME_REAL,min(DATE_REAL),ID_REAL from MYREALTABLE group by NAME_REAL,ID_REAL

But is not whats I need, and also I need only 1 query但这不是我需要的,而且我只需要 1 个查询

Thanks you谢谢

I think the following should work by finding the records which have the minimum and maximum dates per name and joining those two queries.我认为以下应该通过查找每个名称具有最小和最大日期的记录并加入这两个查询来工作。

select 
    mn.NAME_REAL,
    MIN_DATE_REAL,
    ID_REAL_OF_MIN_DATE_REAL,
    MAX_DATE_REAL,
    ID_REAL_OF_MAXDATE_REAL
from
(
    select NAME_REAL,
        DATE_REAL as MIN_DATE_REAL,
        ID_REAL as ID_REAL_OF_MIN_DATE_REAL,
        from (
        select 
            NAME_REAL, 
            ID_REAL, 
            DATE_REAL, 
            row_number() over (partition by NAME_REAL order by DATE_REAL asc) as date_order_asc 
        from MYREALTABLE
        )
    where date_order_asc = 1
) mn
inner join
(
    select NAME_REAL,
        DATE_REAL as MAX_DATE_REAL,
        ID_REAL as ID_REAL_OF_MAX_DATE_REAL,
        from (
        select 
            NAME_REAL, 
            ID_REAL, 
            DATE_REAL, 
            row_number() over (partition by NAME_REAL order by DATE_REAL desc) as date_order_desc 
        from MYREALTABLE
        )
    where date_order_desc = 1
) mx
 on mn.NAME_REAL = mx.NAME_REAL

You can join the two results into a single query result as follows您可以将两个结果合并为一个查询结果,如下所示

select o.NAME_REAL,o.max,o.id_real,t.min,o.id_real from (
select NAME_REAL,max(DATE_REAL) as max,ID_REAL, from MYREALTABLE group by NAME_REAL,ID_REAL)
as o inner join
(select NAME_REAL,min(DATE_REAL),ID_REAL from MYREALTABLE group by NAME_REAL,ID_REAL
) as t on o.NAME_REAL=t.NAME_REAL

Try the below -尝试以下 -

select NAME_REAL,ID_REAL,max(DATE_REAL) as max_date, min(DATE_REAL) as min_date
from MYREALTABLE 
group by NAME_REAL,ID_REAL

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