按列分組並獲取 sql 上的最大和最小 ID

Question

我得到了一張包含以下列的表格：ID_REAL、DATE_REAL、NAME_REAL

我想查詢以獲得這樣的結果，並根據名稱進行分組

NAME | MAX(DATE_REAL) | ID_REAL of the MAX(DATE_REAL) | MIN(DATE_REAL) | ID_REAL of the MIN(DATE_REAL)

我現在不知道怎么做

select NAME_REAL,max(DATE_REAL),ID_REAL from MYREALTABLE group by NAME_REAL,ID_REAL
select NAME_REAL,min(DATE_REAL),ID_REAL from MYREALTABLE group by NAME_REAL,ID_REAL

但這不是我需要的，而且我只需要 1 個查詢

謝謝

Answer 1

我認為以下應該通過查找每個名稱具有最小和最大日期的記錄並加入這兩個查詢來工作。

select 
    mn.NAME_REAL,
    MIN_DATE_REAL,
    ID_REAL_OF_MIN_DATE_REAL,
    MAX_DATE_REAL,
    ID_REAL_OF_MAXDATE_REAL
from
(
    select NAME_REAL,
        DATE_REAL as MIN_DATE_REAL,
        ID_REAL as ID_REAL_OF_MIN_DATE_REAL,
        from (
        select 
            NAME_REAL, 
            ID_REAL, 
            DATE_REAL, 
            row_number() over (partition by NAME_REAL order by DATE_REAL asc) as date_order_asc 
        from MYREALTABLE
        )
    where date_order_asc = 1
) mn
inner join
(
    select NAME_REAL,
        DATE_REAL as MAX_DATE_REAL,
        ID_REAL as ID_REAL_OF_MAX_DATE_REAL,
        from (
        select 
            NAME_REAL, 
            ID_REAL, 
            DATE_REAL, 
            row_number() over (partition by NAME_REAL order by DATE_REAL desc) as date_order_desc 
        from MYREALTABLE
        )
    where date_order_desc = 1
) mx
 on mn.NAME_REAL = mx.NAME_REAL

Answer 2

您可以將兩個結果合並為一個查詢結果，如下所示

select o.NAME_REAL,o.max,o.id_real,t.min,o.id_real from (
select NAME_REAL,max(DATE_REAL) as max,ID_REAL, from MYREALTABLE group by NAME_REAL,ID_REAL)
as o inner join
(select NAME_REAL,min(DATE_REAL),ID_REAL from MYREALTABLE group by NAME_REAL,ID_REAL
) as t on o.NAME_REAL=t.NAME_REAL

Answer 3

嘗試以下 -

select NAME_REAL,ID_REAL,max(DATE_REAL) as max_date, min(DATE_REAL) as min_date
from MYREALTABLE 
group by NAME_REAL,ID_REAL