SQL：獲取一列中的最小值和最大值

Question

我有一個帶有姓名和薪水的employee表。

我想打印這 2 列，其中只有 2 條記錄，即我薪酬最高和最低員工的姓名。

它應該是這樣的：

Name      Salary  
------------------
James       800  
Samanth    3000

以下代碼不是我想要的，我想要 2 列中的最小值和最大值，其中 2 個名稱代表每個值

SELECT 
    name, MIN(salary), MAX(salary)
FROM
    employee

Answer 1

我終於想出了我想要的簡單代碼。

select emp_name, salary
from employees
where salary = (select max(salary) from employees)
union all
select emp_name, salary
from employees
where salary = (select min(salary) from employees);

我不知道聯盟。 謝謝大家的貢獻

Answer 2

您可以通過使用子查詢來做到這一點：

SELECT first_name, salary FROM employees
WHERE salary IN ((SELECT MAX (salary) FROM employees), (SELECT MIN (salary) FROM employees))

Answer 3

這種方式我用過。 你可以這樣做

DECLARE @minsalary varchar(60)
set @minsalary = (select top 1 concat(Name, ' ', salary) from employee where salary= (select min(salary) from employee) 
)

DECLARE @maxsalary varchar(60)
set @maxsalary = (select top 1 concat(Name, ' ', salary) from employee where salary= (select max(salary) from employee) 
)

select concat(@maxsalary, ' ', @minsalary)

Answer 4

最好的方法取決於數據庫，但以下使用標准 SQL：

select max(case when seqnum_asc = 1 then salary end) as min_salary,
       max(case when seqnum_asc = 1 then name end) as min_salary_name,
       max(case when seqnum_desc = 1 then salary end) as max_salary,
       max(case when seqnum_desc = 1 then name end) as max_salary_name      
from (select e.*,
             row_number() over (order by salary asc) as seqnum_asc,
             row_number() over (order by salary desc) as seqnum_desc
      from employee e
     ) e;

Answer 5

有很多方法可以做到這一點。 這只是其中之一。 如果他們的最低/最高工資相同，它也可能提供超過 2 條記錄

聲明 @min int, @max int 從 YourTable 中選擇 @min=min(Salary),@max=max(Salary)

SELECT Name, Salary from YourTable where Salary=@min OR Salary=@max

Answer 6

如果您使用的是 mysql，您可以執行以下操作

1. 按薪水 1 將所有用戶分組連接
2. 使用 'order by limit 1' 的最低工資用戶列表
3. 與第 2 步相同以獲得最高工資
4. 聯合他們

即使超過 1 人有最高/最低工資，這也能解決問題

SELECT * 
FROM   ( 
                SELECT   group_concat(NAME) AS names , 
                         salary , 
                         'minimum' AS remarks 
                FROM     employee 
                GROUP BY salary 
                ORDER BY salary limit 1)tmp 
UNION ALL 
SELECT * 
FROM   ( 
                SELECT   group_concat(NAME) AS names , 
                         salary , 
                         'maximum' AS remarks 
                FROM     employee 
                GROUP BY salary 
                ORDER BY salary DESC limit 1
    )tmp1

樣本輸出

names       salary  remarks
tom,jolly   10      minimum
sally     10001   maximum

Answer 7

你可以試試這個。 示例輸出。

name      MAX(salary)   MIN(salary)
George    9200          9200
James     5000           100
Kanye     3200          3200
Nicole    4500          4500
Samanth   3000          2300
Umut      1500           250
Vladimir  2300           330

示例表值

id  name      salary
 1  James        800
 2  Samanth     3000
 3  Umut        1500
 4  Umut         250
 5  Nicole      4500
 6  George      9200
 7  Kanye       3200
 8  Vladimir    2300
 9  Vladimir    1000
10  Vladimir     330
11  James       5000
12  James        100
13  Samanth     2300

SELECT name, MAX(salary), MIN(salary) FROM employee GROUP BY name;