SQL：获取一列中的最小值和最大值

Question

我有一个带有姓名和薪水的employee表。

我想打印这 2 列，其中只有 2 条记录，即我薪酬最高和最低员工的姓名。

它应该是这样的：

Name      Salary  
------------------
James       800  
Samanth    3000

以下代码不是我想要的，我想要 2 列中的最小值和最大值，其中 2 个名称代表每个值

SELECT 
    name, MIN(salary), MAX(salary)
FROM
    employee

Answer 1

我终于想出了我想要的简单代码。

select emp_name, salary
from employees
where salary = (select max(salary) from employees)
union all
select emp_name, salary
from employees
where salary = (select min(salary) from employees);

我不知道联盟。 谢谢大家的贡献

Answer 2

您可以通过使用子查询来做到这一点：

SELECT first_name, salary FROM employees
WHERE salary IN ((SELECT MAX (salary) FROM employees), (SELECT MIN (salary) FROM employees))

Answer 3

这种方式我用过。 你可以这样做

DECLARE @minsalary varchar(60)
set @minsalary = (select top 1 concat(Name, ' ', salary) from employee where salary= (select min(salary) from employee) 
)

DECLARE @maxsalary varchar(60)
set @maxsalary = (select top 1 concat(Name, ' ', salary) from employee where salary= (select max(salary) from employee) 
)

select concat(@maxsalary, ' ', @minsalary)

Answer 4

最好的方法取决于数据库，但以下使用标准 SQL：

select max(case when seqnum_asc = 1 then salary end) as min_salary,
       max(case when seqnum_asc = 1 then name end) as min_salary_name,
       max(case when seqnum_desc = 1 then salary end) as max_salary,
       max(case when seqnum_desc = 1 then name end) as max_salary_name      
from (select e.*,
             row_number() over (order by salary asc) as seqnum_asc,
             row_number() over (order by salary desc) as seqnum_desc
      from employee e
     ) e;

Answer 5

有很多方法可以做到这一点。 这只是其中之一。 如果他们的最低/最高工资相同，它也可能提供超过 2 条记录

声明 @min int, @max int 从 YourTable 中选择 @min=min(Salary),@max=max(Salary)

SELECT Name, Salary from YourTable where Salary=@min OR Salary=@max

Answer 6

如果您使用的是 mysql，您可以执行以下操作

1. 按薪水 1 将所有用户分组连接
2. 使用 'order by limit 1' 的最低工资用户列表
3. 与第 2 步相同以获得最高工资
4. 联合他们

即使超过 1 人有最高/最低工资，这也能解决问题

SELECT * 
FROM   ( 
                SELECT   group_concat(NAME) AS names , 
                         salary , 
                         'minimum' AS remarks 
                FROM     employee 
                GROUP BY salary 
                ORDER BY salary limit 1)tmp 
UNION ALL 
SELECT * 
FROM   ( 
                SELECT   group_concat(NAME) AS names , 
                         salary , 
                         'maximum' AS remarks 
                FROM     employee 
                GROUP BY salary 
                ORDER BY salary DESC limit 1
    )tmp1

样本输出

names       salary  remarks
tom,jolly   10      minimum
sally     10001   maximum

Answer 7

你可以试试这个。 示例输出。

name      MAX(salary)   MIN(salary)
George    9200          9200
James     5000           100
Kanye     3200          3200
Nicole    4500          4500
Samanth   3000          2300
Umut      1500           250
Vladimir  2300           330

示例表值

id  name      salary
 1  James        800
 2  Samanth     3000
 3  Umut        1500
 4  Umut         250
 5  Nicole      4500
 6  George      9200
 7  Kanye       3200
 8  Vladimir    2300
 9  Vladimir    1000
10  Vladimir     330
11  James       5000
12  James        100
13  Samanth     2300

SELECT name, MAX(salary), MIN(salary) FROM employee GROUP BY name;