如何打印与特定字符串匹配的所有行？

Question

I am intending to print all the lines with their line numbers along with its location within a specific directory which matches a particular string

Example ..

/home/some_dir/file.txt -(LineNo) -(printing_thatlineitself)

I currently have 2 commands with me but both have some shortcomings

find /home/some_dir -type f -exec grep -Hn "Text To Find" {} \;

This above find command seems to work accurately but the issue is that it works quite slow

find /home/some_dir -type f -print0 | xargs -0 grep -Hn -C2 "Text To Find"

This command works comparatively quite faster but it provides inaccurate results. It even prints those lines where my inputted string is not present at all

Can someone provide a solution that works accurately and is fast as well? PS / its fine if the solution doesn't use the find command to achieve this .it just has to be something I can directly run in CLI

Answer 1

正如评论中所建议的，可以使用 grep 非常有效地执行此操作

grep -IHnr "Text to find" .

-I : Process a binary file as if it did not contain matching data (to exclude binary files)

-H : Print the filename for each match

-n : Display the matched lines and their line numbers

-r : Recursively search subdirectories listed

"Text to find" : Search string

. : Directory for search (current directory)

Answer 2

I would not squeeze everything into one command. It is simpler to write a small shell script which combines several utilities. For example,

$ cat script.sh
#!/bin/sh   
IFS='
'
for i in `find . -type f`
do
    awk '
    /Text To Find/ {
        print FILENAME, NR
    }' "$i"
done
$ chmod +x script.sh
$ ./script.sh 
./script.sh 7