[英]How to break a for loop from inside an if statement in Julia?
I am trying to translate a python modelisation (not very effective) into a Julia code (more useful in this context) but I didn't find how to break a for loop and how to print a value in this context.我正在尝试将 python 模型化(不是很有效)转换为 Julia 代码(在这种情况下更有用),但我没有找到如何打破 for 循环以及如何在这种情况下打印值。
Python code Python代码
for i in np.range(1, nt)
if t[x == s] == 100:
s_time = i*dt
print(s_time)
break
Julia code I tried :我试过的朱莉娅代码:
for i = 1:nt
if round.(Int, t[x.==s]) == 100
s_time = i*dt
println(s_time)
break
end
end
The variables here are not important, but dt
is a value that allows me to know the time in [y]
in the for loop in function of i
, and t[x.==s] == 100
allows me to know when I want to break the loop.这里的变量并不重要,但dt
是一个值,它允许我知道i
函数中 for 循环中[y]
中的时间,而t[x.==s] == 100
允许我知道我何时想打破循环。
The Julia code do not returns me any error but do not break and do not print anything. Julia 代码不会返回任何错误,但不会中断也不会打印任何内容。
Full code (for Jupyter Notebook users) :完整代码(适用于 Jupyter Notebook 用户):
# NUMERICS
ti = 30 # surface temperature
td = 1000 # dyke temperature
tel = 30 # right lim temperature
teg = tel # left lim temperature
x1 = 80 # central position dyke 2
x2 = 110 # central position dyke 1
d1 = 24 # dyke diameter
d2 = 10 # dyke diameter
s = 160 # probe position
yd1 = 0 # dyke 1 intrusion year
yd2 = 15 # dyke 2 intrusion year
d = 40 # rock diffusivity
size = 200 # size of the model
ttot = 30; # total time in year
nx = 2001 # cells number
dx = size/(nx-1) # cells size
dt = dx^2/(2.1*d) # frame condition
nt = round(Int, ttot/dt) # frame number
x = LinRange(0, size, nx); # size model
# INITIALISATION
indexing_1_l = round(Int, (x1 - d1/2)*nx/size)
indexing_1_r = round(Int, (x1 + d1/2)*nx/size)
indexing_2_l = round(Int, (x2 - d2/2)*nx/size)
indexing_2_r = round(Int, (x2 + d2/2)*nx/size);
t = ti * ones(nx)
t[indexing_1_l:indexing_1_r] .= td;
using Plots
gr() ;
# PLOTTING LOOP
for i = 1:nt
q = -d*(diff(t)/dx)
dcdt = -diff(q)/dx
t[2:end-1] = t[2:end-1] + dcdt*dt
t[1] = teg
t[end] = tel
if i == round(Int, yd2/dt)
t[indexing_2_l:indexing_2_r] .= td
end
# IF STATEMENT THAT DOESN'T WORK
if round.(Int, t[x.==s]) == 100
s_time = i*dt
println("$s_time")
break
end
if mod(i, 1000) == 0
IJulia.clear_output(true)
pt = plot(x, t, label = :false, c="red", title=" $(round.(Int, i*dt)) [y] - Dyke intrusion",
xlabel="Distance [m]", ylabel="Temperature [°C]", ylims=(0, 1000), size = (800, 600))
Plots.display(pt)
end
end
This will never return true
because an array cannot be equal to a number:这永远不会返回true
因为数组不能等于数字:
if round.(Int, t[x.==s]) == 100
Look at this看这个
julia> [100] == 100
false
It's not completely clear what you want it to mean, but perhaps this不完全清楚你想要它的意思,但也许这个
if all(round.(Int, t[x.==s]) .== 100)
or perhaps any
?或者any
?
you have a syntax error!你有一个语法错误! println(s_time) println(s_time)
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