从 tail -f 只打印花括号之间的行

Question

I have a script that reads several debug logs, appends it to a temp file, then does a tail -f on the debug file so that we can monitor debug events in a single window and easily see when a user action induces an event. There is a bunch of metadata also written to these debug logs that I don't want included in the monitor script's output.

Is there a way I can use sed or awk to print only data that's contained within curly braces (including the curly braces)? The data within braces can, and always does, span multiple lines.

Data might look like this:

DON'T PRINT THIS DATA:!@#%$%^
DON'T "!@#()*& PRINT THIS DATA EITHER
}
DON"T PRINT THIS
{
PRINT THIS DATA BLOCK
AND THIS DATA
AND THIS LINE TOO:!@#(*&
}
DONT:!@# \/PRINT THIS
{
BUT PRINT THIS
}

Answer 1

Using multiple sed

sed -n '/{/,/}/p' InputFile | sed '/^{/d' | sed '/^}/d'

Using Single sed

sed -n '/{/,/}/{/{/!{/}/!p}}' InputFile