[英]How to add annotations to Stack Percentage Barplot in Matplotlib
I want to add values to stacked bar chart using matplotlib.我想使用 matplotlib 向堆积条形图添加值。 So far I've been able to create the stacked bar chart, but I am confused on how to add the annotations.
到目前为止,我已经能够创建堆积条形图,但我对如何添加注释感到困惑。
A similar question has been answered here , but for ggplot. 这里已经回答了一个类似的问题,但对于 ggplot。
I want an output similar to that not the entire graph but just the annotations in middle.我想要的输出类似于不是整个图形,而是中间的注释。
import pandas as pd
import seaborn as sns
import matplotlib.pyplot as plt
data = {'Range':['<10','>10', '>= 20', '<10','>10', '>= 20', '<10','>10', '>= 20'],
'Price':[50,25,25,70,20,10,80,10,10]
'Value':[100,50,50,140,40,20,160,20,20]}
df1 = pd.DataFrame(data)
b1 = df1[(df1['Range'] == '<10']['Price']
b2 = df1[df1['Range'] == '>10']['Price']
b3 = df1[df1['Range'] == '>= 20']['Price']
totals = [i+j+k for i,j,k in zip(b1,b2,b3)]
greenBars = [i / j * 100 for i,j in zip(b1, totals)]
orangeBars = [i / j * 100 for i,j in zip(b2, totals)]
blueBars = [i / j * 100 for i,j in zip(b3, totals)]
barWidth = 0.5
names = ('low', 'medium', 'high')
r = [0,1,2]
plt.bar(r, greenBars, color='#b5ffb9', edgecolor='white', width=barWidth, label = '$<10')
plt.bar(r, orangeBars, bottom=greenBars, color='#f9bc86', edgecolor='white', width=barWidth, label = '$>10')
plt.bar(r, blueBars, bottom=[i+j for i,j in zip(greenBars, orangeBars)], color='#a3acff', edgecolor='white', width=barWidth, label = '$>=20')
plt.xticks(r, names)
plt.xlabel("group")
plt.legend(loc='upper left', bbox_to_anchor=(1,1), ncol=1)
plt.show()
Added code above to create the stacked plot.添加了上面的代码以创建堆叠图。 Desired Output:
期望输出:
For Low category add annotations on stacks by extracting values from column Value
that would be 100, 50 & 50通过提取从列值上叠层低类别添加注解
Value
,这将是100,50&50
For Medium values would be 140, 40 & 20.对于中值,值为 140、40 和 20。
For High values would be 160, 20 & 20.高值将是 160、20 和 20。
ax.patches
.ax.patches
提取条形位置来ax.patches
。
Value
instead of Price
, there needs to be a way to associate the corresponding values.Value
而不是Price
进行注释,需要有一种方法来关联相应的值。
Value
and a corresponding dataframe for Price
.Value
制作一个透视数据框,为Price
一个相应的数据框。 This will ensure corresponding data is in the same location.col_idx
and row_idx
will be used with .iloc
to find the correct value in df_value
, with which to annotate the plot. col_idx
和row_idx
将被用来.iloc
找到正确的值df_value
,与注释的情节。
col_idx
and row_idx
can both be reset or updated in if i%3 == 0
, because there are 3 bars and 3 segments, however, if there are differing numbers of bars and segments, there will need to be different reset conditions. col_idx
和row_idx
都可以在if i%3 == 0
重置或更新,因为有 3 个柱和 3 个段,但是,如果柱和段的数量不同,则需要不同的重置条件。import pandas as pd
import matplotlib.pyplot as plt
# create the dataframe
data = {'Range':['<10','>10', '>= 20', '<10','>10', '>= 20', '<10','>10', '>= 20'],
'Price':[50,25,25,70,20,10,80,10,10],
'Value':[100,50,50,140,40,20,160,20,20]}
df1 = pd.DataFrame(data)
# pivot the price data
df_price = df1.assign(idx=df1.groupby('Range').cumcount()).pivot(index='idx', columns='Range', values='Price')
Range <10 >10 >= 20
idx
0 50 25 25
1 70 20 10
2 80 10 10
# pivot the value data
df_value = df1.assign(idx=df1.groupby('Range').cumcount()).pivot(index='idx', columns='Range', values='Value')
Range <10 >10 >= 20
idx
0 100 50 50
1 140 40 20
2 160 20 20
# set colors
colors = ['#b5ffb9', '#f9bc86', '#a3acff']
# plot the price
ax = df_price.plot.bar(stacked=True, figsize=(8, 6), color=colors, ec='w')
# label the x-axis
plt.xticks(ticks=range(3), labels=['low', 'med', 'high'], rotation=0)
# x-axis title
plt.xlabel('group')
# position the legend
plt.legend(bbox_to_anchor=(1.05, 1), loc='upper left')
# annotate the bar segments
# col and row iloc indices for df_value
col_idx = 0
row_idx = 0
# iterate through each bar patch from ax
for i, p in enumerate(ax.patches, 1):
left, bottom, width, height = p.get_bbox().bounds
v = df_value.iloc[row_idx, col_idx]
if width > 0:
ax.annotate(f'{v:0.0f}', xy=(left+width/2, bottom+height/2), ha='center', va='center')
# use this line to add commas for thousands
# ax.annotate(f'{v:,}', xy=(left+width/2, bottom+height/2), ha='center', va='center')
row_idx += 1
if i%3 == 0: # there are three bars, so update the indices
col_idx += 1
row_idx = 0
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.