字符串到日期时间 BigQuery

Question

I have a column with strings as datetimes. I want to convert the whole column to datetime format.

Example
"19.03.2020 08:14:13"
"30.04.2020 08:57:45"

I tried this:

select *,
PARSE_DATETIME("%d%m%y %H:%M:%S", Example) as Date_example
from xx.yy.zz

but i got an error Failed to parse input string "19.03.2020 08:14:13"

Can anyone help me and tell me why this is not working? Is it because day,month and year are separated by the dot instead of slash?

Answer 1

Consider:

PARSE_DATETIME('%d.%m.%Y %H:%M:%S', example) as Date_example

Rationale:

• your original format specifier is missing the dot separator between the date components

• you want %Y rather than %y for the year component (the former is a 4 digits year, while the later is 2 digits)

We can shorten the query a little with %T :

PARSE_DATETIME('%d.%m.%Y %T', example) as Date_example