想在python中重命名2个具有不同扩展名的文件

Question

I am working in one project where i need to rename the multiple file in same folder and for that i write down the code but when i am running this code then it's throwing the error like "file already exist". is there any way where i can skip those file which is already present with sequqnce and rename the rest of file in sequence, please help me.

Example of file:

0.png
0.xml 

Code which i wrote:

    import os
    png_files = set()
    xml_files = set()
    base_path = r'C://Users//admin//Desktop//anotate'
    for x in os.listdir(base_path):
    name, ext = x.split('.')
    if ext == 'png':
    png_files.add(name)
    elif ext == 'xml':
    xml_files.add(name)
    counter = 0
    for filename in png_files.intersection(xml_files): # For files that are common (same names)
    if filename.exists():
    print ("File exist")
    else:
os.rename(os.path.join(base_path,filename+'.png'),os.path.join(base_path,str(counter)+'.png')) 
#Rename png file
os.rename(os.path.join(base_path,filename+'.xml'),os.path.join(base_path,str(counter)+'.xml')) # 
Rename xml file
counter += 1 # Increment counter   

Answer 1

Please make sure to copy your folder as backup as this will remove your old folder and instead will place a new folder with same name this is just in case anything goes wrong.

from pathlib import Path

directory = Path("./Annotate")
out_dir = Path("./Out")

out_dir.mkdir(exist_ok=True)

pngs = list(directory.glob("*.png"))
xmls = list(directory.glob("*.xml"))

for num, file in enumerate(pngs):
    write_here = out_dir / "{}.png".format(num) 
    write_here.write_bytes(file.read_bytes())
    
for num, file in enumerate(xmls):
    write_here = out_dir / "{}.xml".format(num) 
    write_here.write_bytes(file.read_bytes())
    
for files in directory.iterdir():
    files.unlink()
    
directory.rmdir()
out_dir.rename(directory)

change the base_dir variable to path of your folder containing images and xmls.
output will be generated in the folder named Out in the current working directory .

Example:
say your annotate folder looks like this

/Annotate
--/0.png
--/0.xml
--/1.png
--/1.xml
--/dog.png
--/dog.xml
--/cat.png
--/cat.xml

After running the script The Annotate folder will look like.

/Annotate
--/0.png
--/0.xml
--/1.png
--/1.xml
--/2.png
--/2.xml
--/3.png
--/3.xml

I am not exactly renaming the file but I am making a new directory with file naming format you want.

NOTE:
If you annotate more images ie you run the script again after annotating more images I would recommend that you delete the old Output folder. It should not matter though but for safety!!
Make sure you have latest python installed.

As per request, here is the step by step code explanation!

you import required module

from pathlib import Path

make two path objects :
1. directory specifying your input directory path.
2. out_dir specifying path to temporary output folder

directory = Path("./Annotate")
out_dir = Path("./Out")

Makes a folder specified in the Path object, if folder exists no error is thrown the code continues.

out_dir.mkdir(exist_ok=True)

Makes two separate python list of all the paths inside the selected path object that ends with .png and .xml .

pngs = list(directory.glob("*.png"))
xmls = list(directory.glob("*.xml"))

loops through the python list pngs and xmls and writes down binary data of selected file with the name specified by index of enumerate in the output path object location.

for num, file in enumerate(pngs):
    write_here = out_dir / "{}.png".format(num) 
    write_here.write_bytes(file.read_bytes())

for num, file in enumerate(xmls):
    write_here = out_dir / "{}.xml".format(num) 
    write_here.write_bytes(file.read_bytes())

Deletes everything from the path object specified.
than remove the path object. and rename the temporary path object to old path that was just removed.

for files in directory.iterdir():
    files.unlink()

directory.rmdir()
out_dir.rename(directory)