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Plotly：如何自定义 3D 散点图的符号？

[英]Plotly: How to customize the symbols of a 3D scatter plot?

 原文  2020-09-25 04:02:43  5   1    python/ plot/ 3d/ plotly

问题描述

In the example below:在下面的例子中：

import plotly.express as px
df = px.data.iris()
fig = px.scatter_3d(df, x='sepal_length', y='sepal_width', z='petal_width',
                    color='petal_length', symbol='species')
fig.show()

在此处输入图片说明 symbol is determined by the the 'species' represented by circles, rhombus and squares. symbol由圆形、菱形和正方形代表的'species'决定。 This may not be very clear when sample size gets large and sample points smear the plot.当样本量变大并且样本点涂抹图时，这可能不是很清楚。 How can we customise the symbols, say using circle, square and cross(or other contrasting combination of shapes)?我们如何自定义符号，比如使用圆形、方形和十字形（或其他对比形状的组合）？

Update:更新：

I applied the code on another dataset and the code :我将代码应用于另一个数据集和代码：

fig = px.scatter_3d(df8, x='X', y='Y', z='Z',
                    color='P', symbol='C')

# specify trace names and symbols in a dict
symbols = {'True': 'cross',
           'False':'circle-open'}

# set all symbols in fig
for i, d in enumerate(fig.data):
    fig.data[i].marker.symbol = symbols[fig.data[i].name]

fig.show()

where C has two values: True or False .其中C有两个值： True或False 。 However it caught error:但是它捕获了错误：

---------------------------------------------------------------------------
KeyError                                  Traceback (most recent call last)
<ipython-input-183-ea1e2ec7dd8e> in <module>
     36 # set all symbols in fig
     37 for i, d in enumerate(fig.data):
---> 38     fig.data[i].marker.symbol = symbols[fig.data[i].name]
     39 
     40 fig.show()

KeyError: 'P, True'

Update:更新：

Reproducible example:可重现的例子：

{'ID': {0: '672590',
  1: '672120',
  2: '672090',
  3: '672349',
  4: '672453',
  5: '672560',
  6: '672051',
  7: '880505',
  8: '672593',
  9: '880097',
  10: '891458',
  11: '672091',
  12: '672569',
  13: '672603',
  14: '790030',
  15: '672350',
  16: '673480',
  17: 'I00042',
  18: '880297',
  19: '894620'},
 'X': {0: 0.20111215435497176,
  1: 0.21248998904335528,
  2: 0.2086689759935364,
  3: 0.22337836085443835,
  4: 0.17847099434376115,
  5: 0.24827331723865761,
  6: 0.14411891907440183,
  7: 0.20863940038267367,
  8: 0.166299824101773,
  9: 0.20548401328860527,
  10: 0.18007828100726822,
  11: 0.21887731187605308,
  12: 0.1971207940494219,
  13: 0.19247420041228508,
  14: 0.21605657330040987,
  15: 0.15779241902165092,
  16: 0.22536060645732897,
  17: 0.19268784843224268,
  18: 0.2400112771421119,
  19: 0.22548124117213691},
 'Y': {0: 2473.923076923077,
  1: 2031.1538461538462,
  2: 2383.1923076923076,
  3: 1830.7692307692307,
  4: 1780.2307692307693,
  5: 1194.8461538461538,
  6: 1641.0,
  7: 1563.3076923076924,
  8: 1246.2307692307693,
  9: 931.6153846153846,
  10: 1207.076923076923,
  11: 799.6538461538462,
  12: 560.8461538461538,
  13: 1158.076923076923,
  14: 1221.6923076923076,
  15: 3030.076923076923,
  16: 1178.076923076923,
  17: 552.3846153846154,
  18: 1380.3076923076924,
  19: 1027.5384615384614},
 'Z': {0: 385.84615384615387,
  1: 288.46153846153845,
  2: 281.9230769230769,
  3: 273.61538461538464,
  4: 252.0,
  5: 231.69230769230768,
  6: 213.30769230769232,
  7: 203.3846153846154,
  8: 191.07692307692307,
  9: 189.46153846153845,
  10: 181.07692307692307,
  11: 176.76923076923077,
  12: 173.30769230769232,
  13: 169.6153846153846,
  14: 166.15384615384616,
  15: 165.30769230769232,
  16: 160.53846153846155,
  17: 159.84615384615384,
  18: 159.0,
  19: 145.3846153846154},
 'C': {0: True,
  1: True,
  2: True,
  3: True,
  4: True,
  5: True,
  6: True,
  7: True,
  8: True,
  9: True,
  10: True,
  11: False,
  12: False,
  13: True,
  14: True,
  15: True,
  16: True,
  17: False,
  18: True,
  19: True},
 'P': {0: 'P',
  1: 'P',
  2: 'P',
  3: 'P',
  4: 'P',
  5: 'X',
  6: 'P',
  7: 'P',
  8: 'P',
  9: 'P',
  10: 'P',
  11: 'P',
  12: 'P',
  13: 'P',
  14: 'P',
  15: 'P',
  16: 'P',
  17: 'X',
  18: 'P',
  19: 'P'}}

1 个解决方案

解决方案1
 2 已采纳  2020-09-25 06:14:07

The answer:答案：

# specify trace names and symbols in a dict
symbols = {'setosa': 'cross',
           'versicolor':'circle-open',
           'virginica':'diamond-open'}

# set all symbols in fig
for i, d in enumerate(fig.data):
    fig.data[i].marker.symbol = symbols[fig.data[i].name]

The details:细节：

In this case you can set any marker symbol manually using, for example:在这种情况下，您可以手动设置任何标记符号，例如：

fig.data[<i>].marker.symbol = <symbol>

Where <i> is an integer index specifying which trace you'd like to change, and the <symbol> property for a 3D scatter object is an enumeration that may be specified as one of the following enumeration values:其中<i>是一个整数索引，指定您要更改的跟踪，而 3D 分散对象的<symbol>属性是一个枚举，可以指定为以下枚举值之一：

['circle', 'circle-open', 'square', 'square-open',
'diamond', 'diamond-open', 'cross', 'x']

Example 1 - Single trace:示例 1 - 单个跟踪：

fig.data[2].marker.symbol = 'circle-open'
fig.show()

Plot 1:情节 1：

在此处输入图片说明

Example 2 - Multiple traces:示例 2 - 多个跟踪：

In order to make things a bit more dynamic, you can retrieve all trace names using:为了使事情更加动态，您可以使用以下方法检索所有跟踪名称：

['setosa', 'versicolor', 'virginica']

Then you can specify your own dictionary of names and symbols, and set all symbols for all traces using:然后您可以指定自己的名称和符号字典，并使用以下方法设置所有跟踪的所有符号：

# specify trace names and symbols in a dict
symbols = {'setosa': 'cross',
           'versicolor':'circle-open',
           'virginica':'diamond-open'}

# set all symbols in fig
for i, d in enumerate(fig.data):
    fig.data[i].marker.symbol = symbols[fig.data[i].name]

fig.show()

Plot 2:情节 2：

在此处输入图片说明

Complete code:完整代码：

import plotly.express as px
df = px.data.iris()
fig = px.scatter_3d(df, x='sepal_length', y='sepal_width', z='petal_width',
                    color='petal_length', symbol='species')
#fig.show()

# specify trace names and symbols in a dict
symbols = {'setosa': 'cross',
           'versicolor':'circle-open',
           'virginica':'diamond-open'}

# set all symbols in fig
for i, d in enumerate(fig.data):
    fig.data[i].marker.symbol = symbols[fig.data[i].name]

fig.show()

Edit: Answer to addendum by OP编辑：OP 对附录的回答

What happens here is that you're assigning colors and symbols in px.scatter3d using color='P', symbol='C' .这里发生的情况是您在px.scatter3d使用color='P', symbol='C'分配颜色和符号。 And that has consequences for the trace names which are now, for example, 'name': 'P, True' .这会对现在的跟踪名称产生影响，例如'name': 'P, True' 。 This leads the following to break:这导致以下内容中断：

for i, d in enumerate(fig.data):
    fig.data[i].marker.symbol = symbols[fig.data[i].name]

Judging by your defined symbols dict:根据您定义的符号字典判断：

# specify trace names and symbols in a dict
symbols = {'True': 'cross',
           'False':'circle-open'}

It would appear that you'd only like to distinguish your symbols by the last part of 'name': 'P, True' whics is True or False .看起来您只想通过'name': 'P, True'的最后一部分来区分您的符号'name': 'P, True'是True还是False 。 And you can subset your symbols dict by specifying that in symbols[fig.data[i].name.split(', ')[1]] and thus get:您可以通过在symbols[fig.data[i].name.split(', ')[1]]指定来对您的符号字典进行子集化，从而得到：

在此处输入图片说明

Complete code with data sample:带有数据示例的完整代码：

import pandas as pd
import plotly.express as px

df8 = pd.DataFrame({'ID': {0: '672590',
  1: '672120',
  2: '672090',
  3: '672349',
  4: '672453',
  5: '672560',
  6: '672051',
  7: '880505',
  8: '672593',
  9: '880097',
  10: '891458',
  11: '672091',
  12: '672569',
  13: '672603',
  14: '790030',
  15: '672350',
  16: '673480',
  17: 'I00042',
  18: '880297',
  19: '894620'},
 'X': {0: 0.20111215435497176,
  1: 0.21248998904335528,
  2: 0.2086689759935364,
  3: 0.22337836085443835,
  4: 0.17847099434376115,
  5: 0.24827331723865761,
  6: 0.14411891907440183,
  7: 0.20863940038267367,
  8: 0.166299824101773,
  9: 0.20548401328860527,
  10: 0.18007828100726822,
  11: 0.21887731187605308,
  12: 0.1971207940494219,
  13: 0.19247420041228508,
  14: 0.21605657330040987,
  15: 0.15779241902165092,
  16: 0.22536060645732897,
  17: 0.19268784843224268,
  18: 0.2400112771421119,
  19: 0.22548124117213691},
 'Y': {0: 2473.923076923077,
  1: 2031.1538461538462,
  2: 2383.1923076923076,
  3: 1830.7692307692307,
  4: 1780.2307692307693,
  5: 1194.8461538461538,
  6: 1641.0,
  7: 1563.3076923076924,
  8: 1246.2307692307693,
  9: 931.6153846153846,
  10: 1207.076923076923,
  11: 799.6538461538462,
  12: 560.8461538461538,
  13: 1158.076923076923,
  14: 1221.6923076923076,
  15: 3030.076923076923,
  16: 1178.076923076923,
  17: 552.3846153846154,
  18: 1380.3076923076924,
  19: 1027.5384615384614},
 'Z': {0: 385.84615384615387,
  1: 288.46153846153845,
  2: 281.9230769230769,
  3: 273.61538461538464,
  4: 252.0,
  5: 231.69230769230768,
  6: 213.30769230769232,
  7: 203.3846153846154,
  8: 191.07692307692307,
  9: 189.46153846153845,
  10: 181.07692307692307,
  11: 176.76923076923077,
  12: 173.30769230769232,
  13: 169.6153846153846,
  14: 166.15384615384616,
  15: 165.30769230769232,
  16: 160.53846153846155,
  17: 159.84615384615384,
  18: 159.0,
  19: 145.3846153846154},
 'C': {0: True,
  1: True,
  2: True,
  3: True,
  4: True,
  5: True,
  6: True,
  7: True,
  8: True,
  9: True,
  10: True,
  11: False,
  12: False,
  13: True,
  14: True,
  15: True,
  16: True,
  17: False,
  18: True,
  19: True},
 'P': {0: 'P',
  1: 'P',
  2: 'P',
  3: 'P',
  4: 'P',
  5: 'X',
  6: 'P',
  7: 'P',
  8: 'P',
  9: 'P',
  10: 'P',
  11: 'P',
  12: 'P',
  13: 'P',
  14: 'P',
  15: 'P',
  16: 'P',
  17: 'X',
  18: 'P',
  19: 'P'}})

fig = px.scatter_3d(df8, x='X', y='Y', z='Z',
                    color='P', symbol='C')

# specify trace names and symbols in a dict
symbols = {'True': 'cross',
           'False':'circle-open'}

# set all symbols in fig
for i, d in enumerate(fig.data):
    fig.data[i].marker.symbol = symbols[fig.data[i].name.split(', ')[1]]

fig.show()

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