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使用模型拟合另一组的寓言预测结果

[英]Fable forecast results for one group using a model fit on a different group

I am trying to use a fable model fit on one group's time series to predict onto another group's time series:我正在尝试使用适合一组时间序列的fable模型来预测另一组的时间序列:

library(dplyr)
library(fable)
library(feasts)
library(tsibble)
library(fabletools)

df <- data.frame(
    id = rep(c('A', 'B'), each = 5),
    date = seq(as.Date('2020-01-01'), by = "month", length.out = 10),
    y = rnorm(10)
)

train_tsbl <- as_tsibble(filter(df, id == 'A'), key = id, index = date)
test_tsbl <- as_tsibble(filter(df, id == 'B'), key = id, index = date)

model <- train_tsbl %>%
    model(lm = TSLM(y ~ trend()))

However, when forecasting onto the "test" set – records corresponding to ID 'B', the forecast call returns an empty result for 'B' – the test set.但是,当预测到“测试”集 - 对应于 ID 'B' 的记录时, forecast调用返回一个空结果'B' - 测试集。

> forecast(model, test_tsbl)
# A fable: 0 x 4 [?]
# Key:     id, .model [0]
# … with 4 variables: id <fct>, .model <chr>, date <date>, y <dist>

But for train_tsbl , the following:但是对于train_tsbl ,以下内容:

> forecast(model, train_tsbl)
# A fable: 5 x 5 [1D]
# Key:     id, .model [1]
  id    .model date                   y  .mean
  <fct> <chr>  <date>            <dist>  <dbl>
1 A     lm     2020-01-01  N(0.19, 1.8)  0.191
2 A     lm     2020-02-01 N(-0.12, 1.5) -0.122
3 A     lm     2020-03-01 N(-0.42, 1.3) -0.416
4 A     lm     2020-04-01 N(-0.73, 1.5) -0.730
5 A     lm     2020-05-01    N(-1, 1.8) -1.03 

I can't seem to find any option specifying to predict onto new IDs.我似乎找不到任何指定预测新 ID 的选项。 What is going on here?这里发生了什么?

You're using id as a key, which means you fit a separate model for each key.您使用id作为键,这意味着您为每个键安装了一个单独的模型。 Yet your training data does not contain id==B , so there is no B model.但是您的训练数据不包含id==B ,因此没有B模型。

It is hard to know what you expect here.很难知道您在这里期望什么。 What model do you want to use for the B rows?您想为B行使用什么模型?

If you want to use the A model, then set up the test set with B replaced by A :如果要使用A模型,则设置测试集,其中B替换为A

> forecast(model, test_tsbl %>% mutate(id = 'A'))
# A fable: 5 x 5 [1D]
# Key:     id, .model [1]
  id    .model date            y .distribution 
  <chr> <chr>  <date>      <dbl> <dist>        
1 A     lm     2020-06-01 -0.100 N(-0.10, 0.32)
2 A     lm     2020-07-01 -0.217 N(-0.22, 0.42)
3 A     lm     2020-08-01 -0.338 N(-0.34, 0.56)
4 A     lm     2020-09-01 -0.459 N(-0.46, 0.73)
5 A     lm     2020-10-01 -0.575 N(-0.58, 0.93)

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