numpy 2d：如何仅获取第二列中允许值的第一列中最大元素的索引

Question

Help find a high-performance way to solve the problem: I have a result after neural-network(answers_weight), a category for answers(same len) and allowed categories for current request:

answers_weight = np.asarray([0.9, 3.8, 3, 0.6, 0.7, 0.99]) # ~3kk items
answers_category = [1, 2, 1, 5, 3, 1] # same size as answers_weight: ~3kk items
categories_allowed1 = [1, 5, 8]
res = np.stack((answers_weight, answers_category), axis=1)

I need to know the index(in answers_weight array) of max element, but skip not allowed categories(2,3).

In final, index must be = 2 ("3.0", because "3.8" must be skipped as not-allowed by category)

Answer 1

The easiest way would be to use numpy's masked_arrays to mask your weights according to allowed_categories and then find argmax :

np.ma.masked_where(~np.isin(answers_category,categories_allowed1),answers_weight).argmax()
#2

Another way of doing it using masks (this one assumes unique max weight):

mask = np.isin(answers_category, categories_allowed1)
np.argwhere(answers_weight==answers_weight[mask].max())[0,0]
#2

Answer 2

I also solved this problem using a mask

inds = np.arange(res.shape[0])
# a mask is an array [False  True False False  True False]
mask = np.all(res[:,1][:,None] != categories_allowed1,axis=1)

allowed_inds = inds[mask]
# max_ind is not yet the real answer because the not allowed values are not taken into account
max_ind = np.argmax(res[:,0][mask])
real_ind = allowed_inds[max_ind]