[英]Matlab - How to remove outliers from a set of 2D points?
My question has two parts:我的问题有两个部分:
For example, something like this:例如,这样的事情:
x = [1 3 2 4 2 3 400];
y = [2 3 1 4 2 1 500];
xy = [[1 2] [3 3] [2 1] [4 4] [2 2] [3 1] [400 500]];
result = rmoutliers(xy, 'mean');
The result should look like:结果应如下所示:
result = [[1 2] [3 3] [2 1] [4 4] [2 2] [3 1]]
My goal is to remove outlier points in a set of points like this (the points forming a line at the top):我的目标是删除一组像这样的点中的离群点(在顶部形成一条线的点):
First create an nx2 matrix.首先创建一个 nx2 矩阵。
x = [1 3 2 4 2 3 400]';
y = [2 3 1 4 2 1 500]';
xy = [x, y]
Now xy takes the following form:现在 xy 采用以下形式:
xy =
1 2
3 3
2 1
4 4
2 2
3 1
400 500
Now pass this matrix through rmoutliers:现在通过 rmoutliers 传递这个矩阵:
result = rmoutliers(xy);
The value of result should now be:结果的值现在应该是:
result =
1 2
3 3
2 1
4 4
2 2
3 1
As a note, there is no way to make a 1D array where each point has 2 dimensions because... well then you have a 2-dimensional array by definition.需要注意的是,没有办法制作一个一维数组,其中每个点都有二维,因为……好吧,根据定义,你有一个二维数组。 Keep things simple and just build a 2-dimensional matrix from the start!保持简单,从一开始就构建一个二维矩阵!
The function rmoutliers.m
should resemble something like the following:函数rmoutliers.m
应该类似于以下内容:
function [result] = rmoutliers(x, y, tol)
% rmoutliers: main function,
% removes outliers with absolute value > tol(a scalar)
% out of [x,y] series
dist = calcDist(x, y);
mean = calcMean(dist);
result = zeros(2,length(x));
for i = 1:length(dist)
result(:,i) = [x(i), y(i)];
if abs(dist(i) - mean) > tol
result(:,i) = [-1, -1];
end
end
result(result == -1) = [];
result = reshape(result, 2, []);
end
function [dist] = calcDist(x, y)
%calcDist: calculates absolute value of
% each pair of elements in [x, y]
% (the distance from the origin)
dist = sqrt(x.^2 + y.^2);
end
function [mean] = calcMean(dist)
%calcMean: average of input array
mean = sum(dist) / length(dist);
end
All that goes in its own file rmoutliers.m
in your Documents/MATLAB directory.所有这些都在你的Documents/MATLAB目录中它自己的文件rmoutliers.m
中。 It should be evoked from the main Matlab prompt by typing:它应该通过键入以下内容从主 Matlab 提示中唤起:
x = [1 3 2 4 2 3 400];
y = [2 3 1 4 2 1 500];
result = rmoutliers(x, y, 100);
where 100
is just an example of the tolerance factor that will be used to determine the threshold of difference from the mean of an outlier.其中100
只是容差因子的一个示例,用于确定与异常值均值的差异阈值。
EDIT: forgot to output members of result as pairs.编辑:忘记将结果成员成对输出。 You can use the cell
structure for that.您可以为此使用cell
结构。 After having run the program, type at the prompt:运行程序后,在提示符下键入:
C = cell(1,length(x));
for i = 1:length(x)
C(i) = {result(1,i), result(2,i)};
end
% to read from cell structure:
D = cell2mat(C);
D = reshape(D,2, []);
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