没有余数的除法

Question

I am wanting to generate two random numbers a and b

a divide b should have no remainder

eg 10/ 5 = 2

def calculate(self, *args):
    a = self.a_value.get()
    b = self.b_value.get()
    if a % b == 0:
        c = a // b
        if c == self.answer_value.get():
             print(tk.messagebox.showinfo(title=(f"Answer", {self.answer_value.get()}),
                                         message="You are correct"))
             self.clear_text()
             self.get_random_4()
        else:
             print(tk.messagebox.showinfo(title=(f"Answer ", {self.answer_value.get()}),
                                         message="You are not correct"))
             self.clear_text()
             self.get_random_4()

def get_random_4(self):
    self.a_value.set(random.randint(12, 144))
    self.b_value.set(random.randint(1, 10))
    self.answer_input.delete(0, 'end')
    self.answer_input.focus()

my app keeps on generating random numbers but a divided by has remainder.

Please help :)

Thanks in advance.

Answer 1

Much simpler way of doing it change your number generator to :

self.b_value.set(random.randint(1, 12))
self.a_value.set(self.b_value.get() * random.randint(1, 12))

This way you grantee that your numbers are divisible by each other