如何使用 java stream 将 object 列表分组为 map 和 select 第一个不同类型的 object？

Question

I have data like: List<Object1> list1 .

I need to convert it to Map<String, Object2> map1 .

Code below

map1=list1.stream()    
.collect(Collectors  
.groupingBy(Object1::getCity,Collectors  
.mapping(p -> new Object2(p.getvalue1(),p.getvalue2(),p.getvalue3()),  

here I want to get the first(based on any user defined method) item of Object1 type corresponding to each key));

eg

[
 {name:a,roll:2,id:3,age:24,city:goa},  
 {name:b,roll:3,id:3,age:24,city:Delhi},  
 {name:c,roll:2,id:1,age:27,city:goa}
]

Result:

{  
  id=3:{name:a,city:goa},
  id=1:{name:c,city:goa} 
}

Answer 1

You can use Collectors.toMap and define the merge function to take first one for each key.

Map<String, Object2> map = 
     list1.stream()
          .collect(Collectors.toMap(Object1::getCity,
                          p -> new Object2(p.getvalue1(),p.getvalue2(),p.getvalue3())
                          (a, b) -> a));