C++ 两个模板，相同的名称，相同的签名，不同的类：如何强制编译器使用预期的一个？

Question

I am trying to use the following C++ template:

    _CONSTEXPR20 void swap(_Ty& _Left, _Ty& _Right) noexcept(
    is_nothrow_move_constructible_v<_Ty>&& is_nothrow_move_assignable_v<_Ty>) {
    _Ty _Tmp = _STD move(_Left);
    _Left    = _STD move(_Right);
    _Right   = _STD move(_Tmp);
}

from the Microsoft utility standard header (core), but the compiler keeps using the following template:

inline void swap(thread& _Left, thread& _Right) noexcept {
    _Left.swap(_Right);
}

from the Microsoft thread standard header.

How to force the compiler to use the first implementation?

Answer 1

As mentioned in the comments, the compiler will prefer a non-template overload of a function over one that is a template.

If you need to use the template version, just pass the type argument explicitly:

swap<std::thread>(thread1, thread2);