[英]How to find the max xpath value in python
I'm working on scraping data in Selenium using xpaths.我正在使用 xpaths 在 Selenium 中抓取数据。 I want to iterate across xpaths with differing numeric values.我想遍历具有不同数值的 xpath。 For example, I want to iterate across the following xpath: "//*[@id="content-core"]/div/p[i]"
with i
being the values 1
to n
.例如,我想遍历以下 xpath: "//*[@id="content-core"]/div/p[i]"
其中i
是值1
到n
。
Is there a function or code to find n
, the maximum number in a given Xpath equation, so I know when to stop the loop?是否有函数或代码可以找到给定 Xpath 方程中的最大数n
,以便我知道何时停止循环?
Thanks so much!非常感谢!
You can use a try-except
block, like this:您可以使用try-except
块,如下所示:
from selenium.common.exceptions import NoSuchElementException
i = 1
while True:
try:
xpath = f"//*[@id="content-core"]/div/p[{i}]"
driver.find_element_by_xpath(xpath)
i += 1
except NoSuchElementException:
break
You can use count
to solve it.您可以使用count
来解决它。 For example, assume if you have extract an html
of an url
, as follows:例如,假设您提取了url
的html
,如下所示:
import requests
from lxml import etree
response = requests.get(url)
data = response.text
html = etree.HTML(data)
Then, you can get the length of the label p
.然后,您可以获得标签p
的长度。
len = int(html.xpath('count(//*[@id="content-core"]/div//p)'))
Find the elements len and then loop through them.找到元素 len 然后遍历它们。
n=len(driver.find_elements_by_xpath("//*[@id='content-core']/div/p"))
for i in range(n):
try:
driver.find_element_by_xpath("//*[@id='content-core']/div/p["+i+"]")
except:
break
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