如何根据具有连续相同值的列事件删除数据框中的行

Question

For example, the below is a data frame:

   Index      Name       Action
    0          result    pass
    1          result    fail
    2          result    fail
    3          result    pass
    4          result    fail
    5          result    pass
    6          result    pass
    7          result    pass

Here we are taking reference of "Action" column, consecutive 'pass' or 'fail' will result only last one of the row to be present.

so expected output will be as below:

   Index      Name       Action
    0          result    pass
    2          result    fail
    3          result    pass
    4          result    fail
    7          result    pass

Answer 1

Use Series.ne with Series.shift with -1 for mask for last rows and filter by boolean indexing :

df = df[df['Action'].ne(df['Action'].shift(-1))]
print (df)
     Name Action
0  result   pass
2  result   fail
3  result   pass
4  result   fail
7  result   pass