正则表达式不止一次出现一个符号

Question

My regex is as follows (.*?)add\\(\\${2,}(.*?)\\)

I want this to validate add($arg1, $agr2)

That is to detect more than 1 occurance of '$' within the add function. I want to return all the text before the add function hence i used (.*?) But the {2,} part doesn't seem to work for me.

Answer 1

You can use the capturing group to match as least as possible before add.

Then match a single argument starting with a dollar sign and match 1 or more word characters followed by repeating 1 or more times a comma and again an argument.

Note that (.*?) will also match an empty string.

(.*?)\badd\(\$\w+(?:\h*,\h*\$\w+)+\)

Explanation

• (.*?) Capture group 1, match any char except a newline 0+ times as least as possible
• \\badd A word boundary, then match add
• \\( Match (
• \\$\\w+ match $ and 1+ word characters
• (?: Non capture group
  • \\h*,\\h*\\$\\w+ match a comma between optional horizontal whitespace chars
• )+ Close group and repeat 1+ times
• \\) Match )

See a regex demo