简体   繁体   English

如何减少(子集)列表列表?

[英]How to reduce (subset) list of lists?

I have a list of lists like this:我有一个像这样的列表:

list.ex <- list('a' = c(10,11), 'b' = c(9,10,11), 'c' = c(8,9,10,11), 'd' = c(7,8,9,10,11), 'e' = c(6,7,8,9,10,11), 'f' = c(6,8,9,10,11))

I want to check and remove those lists which are a subset of another list (in the exact order).我想检查并删除作为另一个列表子集的那些列表(按确切顺序)。 eg In this case I want to reduce list.ex such that we are left with list.ex[[e]] and list.ex[[f]] .例如,在这种情况下,我想减少list.ex以便我们留下list.ex[[e]]list.ex[[f]]

is_subsequence determines if a is a subset of b in the same order. is_subsequence确定a是否是b的相同顺序的子集。

library(tidyverse)

is_subsequence <- function(a, b) {
  str_detect(
    paste0(b, collapse = ","),
    fixed(paste0(a, collapse = ","))
  )
}

matches_other takes a vector and determines if it matches more than one vector in list.ex matches_other接受一个向量并确定它是否与list.ex中的多个向量list.ex

matches_other <- function(l) {
  map_lgl(
    list.ex,
    ~is_subsequence(l, .)
  ) %>%
  sum() %>%
  `>`(1)
}

discard is used to remove matches. discard用于删除匹配项。

list.ex %>%
  discard(matches_other)
#> $e
#> [1]  6  7  8  9 10 11
#> 
#> $f
#> [1]  6  8  9 10 11

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM