如何在 Javascript 中计算 ExtraLarge Number 的阶乘？

Question

// Sample Input 
// 25
// Sample OutPut
// 15511210043330985984000000
// Code
const factorial = (n)=>{
let result = 1;
for(let i = 25; i> 0;i--){
    result = result * i;
}
    return result;
}
console.log(factorial(25)); // You will get 1.5511210043330984e+25

But We need Exact solution So for that check the Answer Shared.

Answer 1

// Sample Input 
// 25
// Sample OutPut
// 15511210043330985984000000

// Code

function extraLongFactorials(n) {
  let result = 1;
  for (let i = n; i > 0; i--) {
    result = BigInt(result) * BigInt(i);
  }
  return (result.toString());
}
console.log(extraLongFactorials(25));

Answer 2

Just use the n suffix on your numbers.

 const factorial = n => n ? n * factorial(n - 1n) : 1n; console.log(`25! = ${factorial(25n)}`);