python中的用户输入矩阵（n * n + 1）

Question

this code is out put a[i][j] start with a[0,0] but i want it start with a[1,1] How have i do??

import numpy as np
n = int(input("How many variable you find "))
a = np.zeros((n,n+1))
print('Enter Augmented Matrix:')
for i in range(n):
    for j in range(n+1):
        a[i][j] = float(input( f'a[{i},{j}]= '))
print(a)

Answer 1

Using range(n) starts at 0 included, and n exlcuded, in math this is [0;n[ , to start at 1 do range(1, n) giving you

for i in range(1, n):
    for j in range(1, n + 1):

If you input 4 at first question, then fill with ones you'll get :

[[0. 0. 0. 0. 0.]
 [0. 1. 1. 1. 1.]
 [0. 1. 1. 1. 1.]
 [0. 1. 1. 1. 1.]]

---

If you use the following it goes to far, because arrays are indexed 0-base , so if you say an array is length 5, the box indexes are 0,1,2,3,4

for i in range(1, n + 1):
    for j in range(1, n + 2):

---

SOLUTION

If you want to fill all values, but just change the thing you print for the user, do

for i in range(n):
    for j in range(n + 1):
        a[i][j] = float(input(f'a[{i + 1},{j + 1}]= ')) # +1 there

Answer 2

change this:

   for i in range(n):
        for j in range(n+1):
            a[i][j] = float(input( f'a[{i},{j}]= '))

to this:

for i in range(1,n):
    for j in range(1,n+1):
        a[i][j] = float(input( f'a[{i},{j}]= '))

Similarly you can try

 for i in range(n-1):
     for j in range(n):
         a[i+1][j+1] = float(input( f'a[{i},{j}]= '))

May I ask why do you want to start with a[1][1]?