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如何通过 hargreaves-samani 方程和使用 python 计算每日蒸发量?

[英]How to calculate daily evapotranspiration by hargreaves-samani equation and using python?

I have a ten-year weather data including maximum temperature ( Tmax ), minimum temperature ( Tmin ), rainfall and solar radiation ( Ra ) for each day.我有一个十年的天气数据,包括每天的最高温度 ( Tmax )、最低温度 ( Tmin )、降雨量和太阳辐射 ( Ra )。

At first, I would like to calculate evapotranspiration (ETo) for each day using the following equation:首先,我想使用以下公式计算每天的蒸散量 (ETo):

ETo=0.0023*(((Tmax+Tmin)/2)+17.8)*sqrt(Tmax-Tmin)*Ra

Then, calculation of the monthly and yearly average of all parameters (Tmax,Tmin, Rainfall, Ra and ETo) and print them in Excel format.然后,计算所有参数(Tmax,Tmin, Rainfall, Ra and ETo)的月和年平均值并以 Excel 格式打印。

I have written some parts.我已经写了一些部分。 could you possibly help me with completing it?你能帮我完成它吗? I think it may need a loop .我认为它可能需要一个循环

import numpy as np
import pandas as pd
import math as mh
# load the weather data file
data_file = pd.read_excel(r'weather data.xlsx', sheet_name='city_1')
# defining time
year = data_file['Year']
month = data_file['month']
day = data_file['day']
# defining weather parameters
Tmax = data_file.loc[:,'Tmax']
Tmin = data_file.loc[:,'Tmin']
Rainfall = data_file.loc[:,'Rainfall']
Ra = data_file.loc[:,'Ra']
# adjusting time to start at zero
year = year-year[0]
month=month-month[0]
day=day-day[0]
#calculation process for estimation of evapotranspiration
ET0=(0.0023*(((Tmax+Tmin)/2)+17.8)*(mh.sqrt(Tmax-Tmin))*Ra

Looks like you've got one data row (record) per day.看起来您每天有一个数据行(记录)。

Since you already have Tmax, Tmin, Rainfall, and Sunhours in the row, you could add a net ET0 row with the calculation like this:由于您在行中已经有 Tmax、Tmin、Rainfall 和 Sunhours,您可以使用如下计算添加一个净 ET0 行:

    data_file['ET0'] = data_file.apply(lambda x: 0.0023*(((x.Tmax+x.Tmin)/2)+17.8)*(mh.sqrt(x.Tmax-x.Tmin))*x.Ra, axis=0)

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