[英]How do I iterate through nested vectors?
I have a rather complex ordered internal Grammar representation of my productions consisting of typed std libarary classes:我的作品有一个相当复杂的有序内部语法表示,由类型化的 std 库类组成:
class Grammar {
std::tuple<int, NonTerminal, std::vector<std::vector<Symbol>>> productions;
}
Now I would like to create LR0-Items from this representation.现在我想从这个表示创建 LR0-Items。
From inner to outer:从内到外:
std::vector<Symbol>
represents a rule std::vector<Symbol>
表示规则std::vector<std::vector<Symbol>>
represents an alternative rule of the production. std::vector<std::vector<Symbol>>
表示产生式的替代规则。NonTerminal, std::vector<std::vector<Symbol>>>
represents the lhs of the production NonTerminal, std::vector<std::vector<Symbol>>>
代表产生式的lhsstd::tuple<int, NonTerminal, std::vector<std::vector<Symbol>>>
represents the order of the productions. std::tuple<int, NonTerminal, std::vector<std::vector<Symbol>>>
表示产生式的顺序。 Question: How do I iterate through the productions?问题:如何迭代产品? I am new to c++.我是 C++ 的新手。 As far as I know the way is through an ::iterator
.据我所知,方法是通过::iterator
。 But then, how do I address one nested datatype to build an iterator from it?但是,我如何解决一种嵌套数据类型以从中构建迭代器?
Thanks谢谢
EDIT:编辑:
Instead of std::tuple
I think it's yet better to have the definition consist of two times a std::pair
:而不是std::tuple
我认为让定义包含两次std::pair
更好:
std::pair<int, std::pair<NonTerminal, std::vector<std::vector<Symbol>>> productions;
I try to adopt the answer of user idclev 463035818
我尝试采用用户idclev 463035818
的答案
for( const &auto production : productions.back) {
for( const &auto alternatives : production.back) {
for( const &auto rule : alternatives) {
// ...
}
}
}
Correct ?正确的 ?
To iterate a vector whose elements are of type T
you can use a range based for loop:要迭代元素类型为T
的向量,您可以使用基于范围的 for 循环:
std::vector<T> vect;
for (const auto& element : vect) {
// element is a const reference to elements of vect
// put code here
}
Now, if T
is again a vector, you just replace //put code here
with your code to iterate that vector element
.现在,如果T
再次是一个向量,您只需将//put code here
替换为您的代码以迭代该向量element
。
Nesting containers is not as complicated as you might expect.嵌套容器并不像您想象的那么复杂。 It does not require special treatment.它不需要特殊处理。 If you know how to iterate one vector and get a reference to its elements, then you already do know how to iterate those elements in case they are vectors.如果您知道如何迭代一个向量并获得对其元素的引用,那么您就已经知道如何迭代这些元素,以防它们是向量。
So lets say you have a std::vector<std::vector<Symbol>>>
(I'll skip the tuple, because I suppose you don't want to "iterate" it, but just pick the 3rd element from it).因此,假设您有一个std::vector<std::vector<Symbol>>>
(我将跳过元组,因为我想您不想“迭代”它,而只需从中选择第三个元素)。
std::vector<std::vector<Symbol>>> vect_vect;
for (const auto& vect : vect_vect) {
// here vect is a const reference to std::vector<Symbol>
for (const auto& symbol : vect) {
// here symbol is a const reference to a Symbol
// put your code here
// eg assuming Symbol has a member get_bar
auto foo = symbol.get_bar();
}
}
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