Python打印前三行文本

Question

import requests
from bs4 import BeautifulSoup
import csv


url = "https://alta.ge/phones-and-communications/smartphones.html"
r = requests.get(url)
content = r.text

soup = BeautifulSoup(content, 'html.parser')

a = soup.find_all('div', {'class':'ty-grid-list__item-name'})
for smartphone in a:
    a = smartphone.find('a').get_text()
    print(a)

this is my code when i run it prints names of every item. i only want to print first 3 items, how do i do that?

Answer 1

Instead of using

for smartphone in a:
    a = smartphone.find('a').get_text()
    print(a)

You can try to replace it with:

for smartphone in a:
    if count < 3:
        a = smartphone.find('a').get_text()
        print(a)
        count += 1

Answer 2

You could try using these codes:

import requests
from bs4 import BeautifulSoup
import csv


url = "https://alta.ge/phones-and-communications/smartphones.html"
r = requests.get(url)
content = r.text

soup = BeautifulSoup(content, 'html.parser')

a = soup.find_all('div', {'class':'ty-grid-list__item-name'})
for smartphone in a[:3]: 
    a = smartphone.find('a').get_text()
    print(a)

Answer 3

You can replace this part of your code:

for smartphone in a:
    a = smartphone.find('a').get_text()
    print(a)

With this:

count = 0
for smartphone in a:
    if count < 3:
        a = smartphone.find('a').get_text()
        print(a)
        count += 1

Answer 4

You can replace

for smartphone in a:

with

for smartphone in a[:3]:

to loop trough 3 elements in list only