使用正则表达式在 JSON 对象中查找密码值

Question

I have a big JSON object which contains a lot of different JSON, most of them have the structure below (key: sometext-v1.password, and value: password for example:

"apps":[
        "settings": [
                    {
                       "name" : "sometext-v1.password-v1",
                       "value" : "myPassword"
                    },
                    ...
                    ...

I want to use Regex to extract all passwords by a name which contains 'password' string and its value, but I don't want to iterate the JSON name by name because this takes a lot of time for processing.

I tried this, but it isn't working:

String regex = "\"*password*\":\\s*\".*?\"";

Answer 1

You can use

String regex = "\"name\"\\s*:\\s*\"[^\"]*password[^\"]*\",\\s*\"value\"\\s*:\\s*\"([^\"]*)";

See the regex demo . Details:

• "name" - a literal string
• \\s*:\\s* - a : enclosed with optional whitespaces
• " - a " char
• [^"]*password[^"]* - password enclosed with 0 or more chars other than a "
• ", - a ", string
• \\s* - zero or more whitespaces
• "value" - a literal text
• \\s*:\\s* - a : enclosed with optional whitespaces
• " - a " char
• ([^"]*) - Group 1: any zero or more chars other than " .

See a Java demo:

String s = "\"apps\":[\n        \"settings\": [\n                    {\n                       \"name\" : \"sometext-v1.password-v1\",\n                       \"value\" : \"myPassword\"\n                    },\n                    ...";
String regex = "\"name\"\\s*:\\s*\"[^\"]*password[^\"]*\",\\s*\"value\"\\s*:\\s*\"([^\"]*)";
Matcher m = Pattern.compile(regex).matcher(s);
if (m.find()) {
    System.out.println(m.group(1));
}
// => myPassword