[英]Unable to perform assignment because the left and right sides have a different number of elements. MATLAB ERROR
I try to compute a few matrices using MATLAB.我尝试使用 MATLAB 计算一些矩阵。 After run this code I get a error "Unable to perform assignment because the left and right sides have a different number of elements."
运行此代码后,我收到错误“无法执行分配,因为左侧和右侧的元素数量不同。” After simple debugging i get conclusion that after comment X(j) and Y(j) program run correctly.
经过简单的调试,我得出结论,在注释 X(j) 和 Y(j) 程序运行正确之后。 I looked on some similar problem but I cannot find sth that can help me with above problem
我看了一些类似的问题,但我找不到可以帮助我解决上述问题的东西
clear all
close all
clc
%stale
a1 = 1;
a2 = 1;
a3 = 1;
a4 = 1;
a5 = 1;
%% Napęd 2
X=0; Y=0; Z=0;
th1 = 0; th2 = 0; th3 = 0; th4 = 0; th5 = 0;
%alfa2 = 1;
alfa2 = 0:(pi/12):(pi);
alfa1 = 0; alfa3 = 0; alfa4 = 0; alfa5 = 0;
d5=1; d4=1; d3=1; d2=1; d1=1;
a3 = 1;
a3 = 0.1:(1/14):1;
for j = 1 : length(alfa2)
X(j) = a5*cos(th1)*cos(th4)*cos(th5) + a5*sin(th1)*sin(alfa2(j))*sin(th4)*cos(th5) - a5*cos(th1)*sin(th4)*sin(th5) + a5*sin(th1)*sin(alfa2(j))*cos(th4)*sin(th5) + d4*sin(th1)*cos(alfa2(j)) + a3*cos(th1) + alfa2*cos(th1);
Y(j) = a5*sin(th1)*sin(th4)*cos(th5) - a5*cos(th1)*sin(alfa2(j))*cos(th4)*cos(th5) - a5*sin(th1)*sin(th4)*sin(th5) - a5*cos(th1)*sin(alfa2(j))*cos(th4)*sin(th5) + d4*sin(th1)*cos(alfa2(j)) + a3*cos(th1) + alfa2*cos(th1);
Z(j) = a5*cos(alfa2(j))*sin(th4)*cos(th5) + a5*cos(alfa2(j))*cos(th4)*sin(th5) -d4*sin(alfa2(j)) + d1;
end
figure(1);
subplot(2, 2, 1); plot3(Y, X, Z); grid on; title("Przestrzen XYZ");
xlabel('y'); ylabel('X'); zlabel('Z')
subplot(2, 2, 2); plot(Y, X); grid on; xlabel('Y'); ylabel('X');
title("Plaszczyzna XY");
subplot(2, 2, 3); plot(X, Z); grid on; xlabel('X'); ylabel('Z');
title("Plaszczyzna XZ");
subplot(2, 2, 4); plot(Y, Z); grid on; xlabel('Y'); ylabel('Z');
title("Plaszczyzna YZ");
You are using alpha2
in the end of your equations, which is a vector.您在方程式末尾使用
alpha2
,这是一个向量。 You likely want alpha2(j)
你可能想要
alpha2(j)
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