无法执行分配，因为左侧的索引与右侧的大小不兼容。？

Question

F=[125 250 500 1000 2000 4000];
T = [1.1 1.0 0.85 0.8 0.65 0.55]
V = 4*5*2.8;
L_n = [76 78 81 84 83 80];
L_f = [80 81 86 87 86 82];
fi = [1];
fi(end+1) = 0.8*(V./T)

I want to add the values in to fi however i get the eror "Unable to perform assignment because the indices on the left side are not compatible with the size of the right side."

Answer 1

This is my working code

F = [125 250 500 1000 2000 4000];
T = [1.1 1.0 0.85 0.8 0.65 0.55];
V = 56;
L_n = [76 78 81 84 83 80];
L_f = [80 81 86 87 86 82];
fi = 0.8 * (V ./ T);

and if you want the 1 at the beginning of the array, you can add

fi = [1, fi];

.

Answer 2

Matlab matrices with more than 1 dimesion must have same number of elements for each value in one of the dimensions.

In your case, when fi is declared its dimension is 1x1 . And you are trying to add 6 elements on the 2nd position of the first dimension. So, if that worked, you would end up with something like this: [[1],[a1 a2 a3 a4 a5 a6]] . But that is not allowed.

If you still want to do that, you may want to use a cell array . Which allows you to add different elements.

Here you have an example:

fi = {1}
fi{end+1} = 0.8*(V./T)

Notice that some functions like sum won't work on a cell array and you would have to do some conversions.

On the other hand if you expected to have a different output like this: [1 a1 a2 a3 a4 a5 a6] (like sugested on another answer). You may have different options including horzcat :

fi = horzcat([1],0.8*(V./T))