[英]Why is the array not printing out here? (c++)
The array I have is我的数组是
int age[5] = {11,2,23,4,15}
but it does not print out 11,2,23,4, 15
.但它不会打印出11,2,23,4, 15
。
#include <iostream>
#include <array>
using namespace std;
int main() {
int age[5] = {11,2,23,4,15};
cout << age[5] << endl;
}
The name of the array is not age[5]
.数组的名称不是age[5]
。
The name of the array is age
.数组的名称是age
。
The expression age[5]
represents the array's sixth element, which does not exist.表达式age[5]
表示数组的第六个元素,该元素不存在。
In fact, there is no built-in logic for printing a whole array in a formatted manner, so even cout << age << endl
is not correct.事实上,没有以格式化方式打印整个数组的内置逻辑,所以即使cout << age << endl
也不正确。
If you want to print the array, do it element-by-element in a loop.如果要打印数组,请在循环中逐个元素地打印。
Arrays are 0-indexed. Arrays 是 0 索引的。 In your example, the valid indexes are 0..4.在您的示例中,有效索引为 0..4。 You are trying to print a single int
from age[5]
, which is out of bounds.您正在尝试从age[5]
打印单个int
,这是越界的。
You need to loop through the indexes of the array, eg:您需要遍历数组的索引,例如:
#include <iostream>
using namespace std;
int main() {
int age[5] = {11,2,23,4,15};
for(int i = 0; i < 5; ++i) {
cout << age[i] << " ";
}
cout << endl;
}
Alternatively:或者:
#include <iostream>
#include <array>
using namespace std;
int main() {
array<int, 5> age{11,2,23,4,15};
for(int val : age) {
cout << val << " ";
}
cout << endl;
}
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