比较 JSON 值并识别差异 -Snowflake SQL

Question

I am trying to compare the set of two JSON values for every transaction and extract specific values from the below.. I want to extract the following values cCode,dCode,hcps and mod..Can you please guide me on the snowflake SQL syntax for the same.. The first JSON is done by coder and the second json by auditor

1st json
[
  {
    "cCode": "7832",
    "Date": "08/26/2020",
    "ID": "511",
    "description": "holos",
    "dgoses": [
      {
        "description": "disease",
        "dCode": "Y564",
        "CodeAllId": "8921",
        "messages": [
          ""
        ],
        "sequenceNumber": 1
      },
      {
        "description": "acute pain",
        "dCode": "U3321",
        "CodeAllId": "33213",
        "messages": [
          ""
        ],
        "sequenceNumber": 2
      },
      {
        "description": "height",
        "dCode": "U1111",
        "CodeAllId": "33278",
        "messages": [
          ""
        ],
        "sequenceNumber": 3
      },
      {
        "description": "PIDEMIA ",
        "dCode": "H8811",
        "CodeAllId": "90000",
        "messages": [
          ""
        ],
        "sequenceNumber": 4
      }
    ],
    "familyPlan": "",
    "hcpc": 5,
    "id": "",
    "isEPS": false,
    "mod": "67",
    "originalUnitAmount": "8888",
    "type": "CHARGE",
    "unitAmount": "9000",
    "vId": "90001"
  },
  {
    "cCode": "900114",
    "Date": "08/26/2020",
    "ID": "523",
    "description": "heart valve",
    "dgoses": [
      {
        "description": "Fever",
        "dCode": "J8923",
        "CodeAllId": "892138",
        "messages": [
          ""
        ],
        "sequenceNumber": 1
      }
    ],
    "familyPlan": "",
    "hcpc": 1,
    "id": "",
    "mod": "26",
    "originalUnitAmount": "19039",
    "type": "CHARGE",
    "unitAmount": "1039",
    "vId": "5113"
  }
]

2nd JSON
[
  {
    ""cCode"": ""78832"",
    ""Date"": ""08/26/2020"",
    ""ID"": ""511"",
    ""description"": ""holos"",
    ""dgoses"": [
      {
        ""description"": ""disease"",
        ""dCode"": ""Y564"",
        ""CodeAllId"": ""8921"",
        ""messages"": [
          """"
        ],
        ""sequenceNumber"": 1
      },
      {
        ""description"": ""acute pain"",
        ""dCode"": ""U3321"",
        ""CodeAllId"": ""33213"",
        ""messages"": [
          """"
        ],
        ""sequenceNumber"": 2
      },
      {
        ""description"": ""height"",
        ""dCode"": ""U41111"",
        ""CodeAllId"": ""33278"",
        ""messages"": [
          """"
        ],
        ""sequenceNumber"": 3
      },
      {
        ""description"": ""PIDEMIA "",
        ""dCode"": ""H8811"",
        ""CodeAllId"": ""90000"",
        ""messages"": [
          """"
        ],
        ""sequenceNumber"": 4
      }
    ],
    ""familyPlan"": """",
    ""hcpc"": 8,
    ""id"": """",
    ""isEPS"": false,
    ""mod"": ""67"",
    ""originalUnitAmount"": ""8888"",
    ""type"": ""CHARGE"",
    ""unitAmount"": ""9000"",
    ""vId"": ""90001""
  },
  {
    ""cCode"": ""900114"",
    ""Date"": ""08/26/2020"",
    ""ID"": ""523"",
    ""description"": ""heart valve"",
    ""dgoses"": [
      {
        ""description"": ""Fever"",
        ""dCode"": ""J8923"",
        ""CodeAllId"": ""892138"",
        ""messages"": [
          """"
        ],
        ""sequenceNumber"": 1
      }
    ],
    ""familyPlan"": """",
    ""hcpc"": 1,
    ""id"": """",
    ""mod"": ""126"",
    ""originalUnitAmount"": ""19039"",
    ""type"": ""CHARGE"",
    ""unitAmount"": ""1039"",
    ""vId"": ""5113""
  }
]

And I am looking for a result as the below:

 Billid ctextid cCode-Coder cCode-Auditor   deletedccode    added-ccode dCode-Coder
dCode-Auditor   deleted-dcode   added-dcode hcpc-coder  hcpc-auditor    deletedhcpc addedhcpc   mod-coder   mod-auditor deletedmod  addedmod
 7111   89321   7832,900114 78832,900114    7832    78832   Y564,U3321,U1111,H8811,J8923    Y564,U3321,U41111,H8811,J8923   U1111   U41111  5,1 8,1 5   8   67,26   67,126  26  126

Can anyone please help me here

sql Tried

with cte4 as
  
(
  select info:dCode as dtcode
  from cte3, lateral flatten( input => saveinfo:dgoses )
)
select  dCode from cte4, lateral flatten( input => dtcode )

This gives an error straightaway for using:

I have tried the code with the SQL server version but I need to know how to map the JSON functions to the Snowflake SQL version..Can you please help here..

    with I as

( select , dense_rank() over (order by Billid, Ctextid) as tid, dense_rank() over (partition by Billid, Ctextid order by Created) as n from ##input1 ), D as ( select I. , mk.[key] as mk, m. , dk.[key] as dk, d. from I cross apply openjson(info) mk cross apply openjson(mk.value) with ( cCode nvarchar(max) '$.cCode', dgoses nvarchar(max) '$.dgoses' as json ) m cross apply openjson(dgoses) dk cross apply openjson(dk.value) with ( dCode nvarchar(max) '$.dCode' ) d ), C as ( select * from D where n = 1 ), A as ( select * from D where n = 2 ) select Billid, codedby, Ctextid,

 (
     select string_agg(cCode, ',') within group (order by mk)
     from 
     (
         select distinct cCode, mk
         from C
         where tid = t.tid
     ) d
 ) as cCodeCoder,
 (
     select string_agg(cCode, ',') within group (order by mk)
     from 
     (
         select distinct cCode, mk
         from A
         where tid = t.tid
     ) d
 ) as cCodeAuditor,
 (
     select string_agg(cCode, ',')
     from
     (
         select cCode
         from C
         where tid = t.tid
         except
         select cCode
         from A 
         where tid = t.tid
     ) d
 ) as deletedcCode,
 (
     select string_agg(cCode, ',')
     from
     (
         select cCode
         from A
         where tid = t.tid
         except
         select cCode
         from C
         where tid = t.tid
     ) d
 ) as addedcCode,

 (
     select string_agg(dCode, ',') within group (order by mk, dk)
     from 
     (
         select distinct dCode, mk, dk
         from C
         where tid = t.tid
     ) d
 ) as dCodeCoder,
 (
     select string_agg(dCode, ',') within group (order by mk, dk)
     from 
     (
         select distinct dCode, mk, dk
         from A
         where tid = t.tid
     ) d
 ) as dCodeAuditor,
 (
     select string_agg(dCode, ',')
     from
     (
         select dCode
         from C
         where tid = t.tid
         except
         select dCode
         from A 
         where tid = t.tid
     ) d
 ) as deleteddCode,
 (
     select string_agg(dCode, ',')
     from
     (
         select dCode
         from A
         where tid = t.tid
         except
         select dCode
         from C
         where tid = t.tid
     ) d
 ) as addeddCode

from I as t where n = 1

Thanks, Arun

Answer 1

I'm not entirely sure how you need the data, but you're trying to get "cCode, dCode, hcps and mod" (assuming hcps is actually hcpc). The problem is cCode, hcpc, and mod are all on the same level of the JSON. dCode is not. It's nested one layer down from the other properties and is a one to many relationship. This could be flattened out to two tables with a 1:MANY relationship, or it could be flattened out in a single table repeating the cCode, hcpc, and mod values. This example shows the second option:

-- I created a table named FOO and added your JSON as a variant
create temp table foo(v variant);

with
JSON(C_CODE, DGOSES, HCPC, "MOD") as
(
select   "VALUE":cCode::int         as C_CODE
        ,"VALUE":dgoses             as DGOSES
        ,"VALUE":hcpc::int          as HCPS
        ,"VALUE":mod::int           as "MOD"
from foo, lateral flatten(v)
)
select C_CODE, HCPC, "MOD", "VALUE":dCode::string as D_CODE
from JSON, lateral flatten(DGOSES);

This creates a table like this:

C_CODE    HCPC    MOD    D_CODE
  7832       5     67    Y564
  7832       5     67    U3321
  7832       5     67    U1111 
  7832       5     67    HBB11
900114       1     26    J8923