将 JSON object 列值吐到雪花上的新列中（SQL）

Question

I want to split a json column that has multiple values as shown in the picture below into new columns. I'm using snowflake cause that's where the data is located.

like for example, I want name , predicted , level , score all as new column.

Answer 1

So with this CTE to provide the input/data:

with data as (
SELECT '---
- trackingId: 0
  name: English
  predicated: 6
  level: higher
  score: 6' as subjects
)

lets strip that in parts:

select d.*
    ,s.seq
    ,s.value as raw
    ,trim(trim(s.value,'-'),' ') as trimmed 
    ,split(trimmed,':') as parts
    ,trim(parts[0]) as key
    ,trim(parts[1]) as val
    ,iff(key='name', val,null) as name
    ,iff(key='predicated', val,null) as predicated
    ,iff(key='level', val,null) as level
    ,iff(key='score', val,null) as score
from data as d,
table(split_to_table(d.subjects, '\n')) s
where trimmed <> ''

gives:

SUBJECTS	SEQ	RAW	TRIMMED	PARTS	KEY	VAL	NAME	PREDICATED	LEVEL	SCORE
--- - trackingId: 0 name: English predicated: 6 level: higher score: 6	1	- trackingId: 0	trackingId: 0	[ "trackingId", " 0" ]	trackingId	0
--- - trackingId: 0 name: English predicated: 6 level: higher score: 6	1	name: English	name: English	[ "name", " English" ]	name	English	English
--- - trackingId: 0 name: English predicated: 6 level: higher score: 6	1	predicated: 6	predicated: 6	[ "predicated", " 6" ]	predicated	6		6
--- - trackingId: 0 name: English predicated: 6 level: higher score: 6	1	level: higher	level: higher	[ "level", " higher" ]	level	higher			higher
--- - trackingId: 0 name: English predicated: 6 level: higher score: 6	1	score: 6	score: 6	[ "score", " 6" ]	score	6				6

So we can then roll that back up:

select seq
    ,max(name) as name
    ,max(predicated) as predicated
    ,max(level) as level
    ,max(score) as score
from (
    select d.*
        ,s.seq
        ,trim(trim(s.value,'-'),' ') as trimmed 
        ,split(trimmed,':') as parts
        ,trim(parts[0]) as key
        ,trim(parts[1]) as val
        ,iff(key='name', val,null) as name
        ,iff(key='predicated', val,null) as predicated
        ,iff(key='level', val,null) as level
        ,iff(key='score', val,null) as score
    from data as d,
    table(split_to_table(d.subjects, '\n')) s
    where trimmed <> ''
)
group by seq;

giving:

SEQ	NAME	PREDICATED	LEVEL	SCORE
1	English	6	higher	6

Answer 2

You can use the DOC to flatten the JSON data into different columns.