程序使用线程（）和子进程（）运行一段时间

Question

I want to run multiple commands on my liunx os so I create a script to run multiple commands but some command take too much time to execute but I want terminate the commands which take more then 1 min to execute. How can i do that?

import subprocess
import threading
import time
from time import sleep

def prog(line):
    def worker(line):
        print(line)
        subprocess.call(line, shell=True )

    t = threading.Thread(target=worker, args=(line,))
    t.start()
    
f=open("a",'r')
for line in f:
    prog(line)

Answer 1

subprocess.call has a timeout parameter.
It kills the command after a given timout (in seconds) and raises TimeoutExpired .

import subprocess
import threading

def prog(line):
    def worker(line):
        print(line)
        try:
            subprocess.call(line, shell=True, timeout=60)
        except subprocess.TimeoutExpired as e:
            print(e)

    t = threading.Thread(target=worker, args=(line,))
    t.start()
    
f=open("a",'r')
for line in f:
    prog(line)

Here a runnable minimal example: https://ideone.com/ZToaJU

---

Another hint, while not asked for: you don't need to pass args=(line,) to the worker function. As it is declared as a nested function, it already has access to the line variable of prog :

import subprocess
import threading

def prog(line):
    def worker():
        print(line)
        try:
            subprocess.call(line, shell=True, timeout=60)
        except subprocess.TimeoutExpired as e:
            print(e)

    t = threading.Thread(target=worker)
    t.start()
    
f=open("a",'r')
for line in f:
    prog(line)